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Katen [24]
3 years ago
8

PLZZZ SOMEONE HELP MEE

Mathematics
2 answers:
olya-2409 [2.1K]3 years ago
7 0

What grade homework is that?

Over [174]3 years ago
4 0

Answer:

c

Step-by-step explanation:

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What is the solution set for - 4x + 10 = 5(x + 11)? HELPPPPPPP​
Scorpion4ik [409]

Answer:

-5

Step-by-step explanation:

-4x +10 =5(x +11)

-4x +10 =5x +55

-4x - 5x =55 - 10

-9x =45

x=-45 :9

x=-5

7 0
3 years ago
Identify the polygon with vertices A(5,0), B(2,4), C(−2,1), and D(1,−3), and then find the perimeter and area of the polygon. HE
inn [45]

Answer:

Part 1) The polygon is a square

Part 2) The perimeter is equal to 20\ units

Part 3) The area is equal to 25\ units^{2}

Step-by-step explanation:

we have

A(5,0), B(2,4), C(-2,1),D(1,-3)

Plot the points

see the attached figure

we know that

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

Find the distance AB

A(5,0),B(2,4)

substitute in the formula

d=\sqrt{(4-0)^{2}+(2-5)^{2}}

d=\sqrt{(4)^{2}+(-3)^{2}}

d=\sqrt{25}

AB=5\ units

Find the distance BC

B(2,4), C(-2,1)

substitute in the formula

d=\sqrt{(1-4)^{2}+(-2-2)^{2}}

d=\sqrt{(-3)^{2}+(-4)^{2}}

d=\sqrt{25}

BC=5\ units

Find the distance CD

C(-2,1),D(1,-3)

substitute in the formula

d=\sqrt{(-3-1)^{2}+(1+2)^{2}}

d=\sqrt{(-4)^{2}+(3)^{2}}

d=\sqrt{25}

CD=5\ units

Find the distance AD

A(5,0),D(1,-3)

substitute in the formula

d=\sqrt{(-3-0)^{2}+(1-5)^{2}}

d=\sqrt{(-3)^{2}+(-4)^{2}}

d=\sqrt{25}        

AD=5\ units

we have that

AB=BC=CD=AD

Find the distance BD (diagonal)

B(2,4),D(1,-3)

substitute in the formula

d=\sqrt{(-3-4)^{2}+(1-2)^{2}}

d=\sqrt{(-7)^{2}+(-1)^{2}}

BD=\sqrt{50}\ units        

<em>Verify if the polygon is a square</em>

If the triangle BDA is a right triangle, then the polygon is a square

Applying the Pythagoras theorem

BD^{2}=AD^{2}+AB^{2}

substitute

(\sqrt{50})^{2}=5^{2}+5^{2}

50=50 -----> is true

so

The triangle BDA is a right triangle

therefore

The polygon is a square

<em>Find the Area of the polygon</em>

The area of a square is equal to

A=b^{2}

we have

b=5\ units

A=5^{2}=25\ units^{2}

<em>Find the perimeter of the polygon</em>

The perimeter of a square is equal to

P=4b

we have

b=5\ units

P=4(5)=20\ units

6 0
3 years ago
leona has 4 nickles,6 pennies, 4 dimes, and 2 quarter in a change purse.Leona lets her little sister pick a coin at random.if da
victus00 [196]
The probability would be 6/16 or 37.5% because there are 16 coins in total and 6 of them are worth more than 5 cents. :)
4 0
3 years ago
All you need is on the photo
mariarad [96]

Answer:

4^{-3}

Step-by-step explanation:

We\ are\ given\ that,\\4^4*4^{-8}*4\\We\ know\ that,\ for\ any\ real\ number\ n, n^a*n^b=n^{(a+b)}\\Hence,\\First,\ lets\ write\ all\ the\ terms\ in\ an\ exponential\ form.\\4^4*4^{-8}*4^1\\=4^{(4+(-8)+1)}\\=4^{(5-8)}\\=4^{-3}

5 0
3 years ago
X+y+z =4
cestrela7 [59]
<span><span> <span>Akar akar persamaan kuadrat 2x² - 3x -1 = 0 adalah x1 dan x2. Persamaan kuadrat baru yang akar akarnya satu lebih kecil dari dua kali akar akar persamaan kuadrat di atas adalah ........</span></span><span><span><span>A.x² - x - 4 = 0</span><span>B.x² + 5x - 4 = 0</span><span>C.x² - x + 4 = 0</span></span><span><span>D.x² + x + 4 = 0</span><span>E.x² - 5x - 4 = 0</span></span></span><span>Jawaban : A
Penyelesaian : 
Akar-akar persamaan lama :  x1 dan x2
                                             
Akar-akar persamaan baru :  xA dan xB
                                             xA = 2x1 - 1
                                             xB = 2x2 - 1
                                             xA + xB  = (2x1 - 1) + (2x2 - 1)
                                                           = 2 (x1 + x2) - 2
                                                           = 2 () - 2
                                                           = 3 - 2
                                              xA + xB = 1
    
                                              xA . xB = (2x1 - 1) (2x2 - 1)
                                                          = 4 x1.x2 - 2(x1 + x2) + 1
                                                          = 4.(-) - 2() + 1
                                                          = -2 - 3 + 1
                                              xA . xB = -4
    
Jadi persamaan kuadrat baru : x² - (xA + xB)x + xA . xB = 0
                                              x² - x - 4 = 0

</span></span>
4 0
3 years ago
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