PLZZZ SOMEONE HELP MEE

What is the solution set for - 4x + 10 = 5(x + 11)? HELPPPPPPP

Scorpion4ik [409]

Answer:

-5

Step-by-step explanation:

-4x +10 =5(x +11)

-4x +10 =5x +55

-4x - 5x =55 - 10

-9x =45

x=-45 :9

x=-5

7 0

3 years ago

Identify the polygon with vertices A(5,0), B(2,4), C(−2,1), and D(1,−3), and then find the perimeter and area of the polygon. HE

inn [45]

Answer:

Part 1) The polygon is a square

Part 2) The perimeter is equal to $20\ units$

Part 3) The area is equal to $25\ units^{2}$

Step-by-step explanation:

we have

$A(5,0), B(2,4), C(-2,1),D(1,-3)$

Plot the points

see the attached figure

we know that

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Find the distance AB

$A(5,0),B(2,4)$

substitute in the formula

$d=\sqrt{(4-0)^{2}+(2-5)^{2}}$

$d=\sqrt{(4)^{2}+(-3)^{2}}$

$d=\sqrt{25}$

$AB=5\ units$

Find the distance BC

$B(2,4), C(-2,1)$

substitute in the formula

$d=\sqrt{(1-4)^{2}+(-2-2)^{2}}$

$d=\sqrt{(-3)^{2}+(-4)^{2}}$

$d=\sqrt{25}$

$BC=5\ units$

Find the distance CD

$C(-2,1),D(1,-3)$

substitute in the formula

$d=\sqrt{(-3-1)^{2}+(1+2)^{2}}$

$d=\sqrt{(-4)^{2}+(3)^{2}}$

$d=\sqrt{25}$

$CD=5\ units$

Find the distance AD

$A(5,0),D(1,-3)$

substitute in the formula

$d=\sqrt{(-3-0)^{2}+(1-5)^{2}}$

$d=\sqrt{(-3)^{2}+(-4)^{2}}$

$d=\sqrt{25}$

$AD=5\ units$

we have that

AB=BC=CD=AD

Find the distance BD (diagonal)

$B(2,4),D(1,-3)$

substitute in the formula

$d=\sqrt{(-3-4)^{2}+(1-2)^{2}}$

$d=\sqrt{(-7)^{2}+(-1)^{2}}$

$BD=\sqrt{50}\ units$

Verify if the polygon is a square

If the triangle BDA is a right triangle, then the polygon is a square

Applying the Pythagoras theorem

$BD^{2}=AD^{2}+AB^{2}$

substitute

$(\sqrt{50})^{2}=5^{2}+5^{2}$

$50=50$ -----> is true

so

The triangle BDA is a right triangle

therefore

The polygon is a square

Find the Area of the polygon

The area of a square is equal to

$A=b^{2}$

we have

$b=5\ units$

$A=5^{2}=25\ units^{2}$

Find the perimeter of the polygon

The perimeter of a square is equal to

$P=4b$

we have

$b=5\ units$

$P=4(5)=20\ units$

6 0

3 years ago

leona has 4 nickles,6 pennies, 4 dimes, and 2 quarter in a change purse.Leona lets her little sister pick a coin at random.if da

victus00 [196]

The probability would be 6/16 or 37.5% because there are 16 coins in total and 6 of them are worth more than 5 cents. :)

4 0

3 years ago

All you need is on the photo

mariarad [96]

Answer:

$4^{-3}$

Step-by-step explanation:

$We\ are\ given\ that,\\4^4*4^{-8}*4\\We\ know\ that,\ for\ any\ real\ number\ n, n^a*n^b=n^{(a+b)}\\Hence,\\First,\ lets\ write\ all\ the\ terms\ in\ an\ exponential\ form.\\4^4*4^{-8}*4^1\\=4^{(4+(-8)+1)}\\=4^{(5-8)}\\=4^{-3}$

5 0

3 years ago

X+y+z =4

cestrela7 [59]

Akar akar persamaan kuadrat 2x² - 3x -1 = 0 adalah x1 dan x2. Persamaan kuadrat baru yang akar akarnya satu lebih kecil dari dua kali akar akar persamaan kuadrat di atas adalah ........A.x² - x - 4 = 0B.x² + 5x - 4 = 0C.x² - x + 4 = 0D.x² + x + 4 = 0E.x² - 5x - 4 = 0Jawaban : A
Penyelesaian :
Akar-akar persamaan lama : x1 dan x2

Akar-akar persamaan baru : xA dan xB
 xA = 2x1 - 1
 xB = 2x2 - 1
 xA + xB = (2x1 - 1) + (2x2 - 1)
 = 2 (x1 + x2) - 2
 = 2 () - 2
 = 3 - 2
 xA + xB = 1

 xA . xB = (2x1 - 1) (2x2 - 1)
 = 4 x1.x2 - 2(x1 + x2) + 1
 = 4.(-) - 2() + 1
 = -2 - 3 + 1
 xA . xB = -4

Jadi persamaan kuadrat baru : x² - (xA + xB)x + xA . xB = 0
 x² - x - 4 = 0

4 0

3 years ago