The force required to pull one of the microscope sliding at a constant speed of 0.28 m/s relative to the other is zero.
<h3>
Force required to pull one end at a constant speed</h3>
The force required to pull one of the microscope sliding at a constant speed of 0.28 m/s relative to the other is determined by applying Newton's second law of motion as shown below;
F = ma
where;
- m is mass
- a is acceleration
At a constant speed, the acceleration of the object will be zero.
F = m x 0
F = 0
Thus, the force required to pull one of the microscope sliding at a constant speed of 0.28 m/s relative to the other is zero.
Learn more about constant speed here: brainly.com/question/2681210
Answer: Because of the polarity of water molecules
Molecular <u>cohesion</u> is the attraction that molecules have for others of their same type. Depending on the intensity of this attraction, a substance is in a solid, liquid or gaseous state.
In this sense, water (
) can stick to itself through hydrogen bonds, because a water molecule consists of 2 hydrogen atoms attached to 1 oxygen atom.
The oxygen atom tends to monopolize more electrons and keeps them away from hydrogen. Then, it can be said that a water molecule will have a negative side (oxygen) and a positive side (hydrogen).
<u>Thanks to this polarity</u>, water molecules can stick together with the formation of<u> hydrogen bonds</u> to attract a partial positive charge of hydrogen and a more electronegative atom, such as oxygen.
Answer:0.3
Explanation:
Given
velocity of car=15 m/s
truck brought to halt in a distance of 38 m
We know
Final velocity (v)=0
(deceleration)
Therefore minimum coefficient of friction \mu will be
Answer:
48 m/s
Explanation:
The time is 10 seconds
The speed of the car after 10 seconds when the relationship is 4.8 m/s^2 × time can be calculated as follows
= 4.8 × 10
= 48
Hence the speed is 48 m/s
Answer:
um it well it will be 19.6 d) 9.8 J
Explanation:
