Answer: the interest is $8137.8
Step-by-step explanation:
We would apply the formula for determining compound interest which is expressed as
A = P(1+r/n)^nt
Where
A = total amount in the account at the end of t years
r represents the interest rate.
n represents the periodic interval at which it was compounded.
P represents the principal or initial amount deposited
From the information given,
P = $62,604.18
r = 13% = 13/100 = 0.13
n = 1 because it was compounded once in a year.
t = 1 year
Therefore,.
A = 62604.18(1 + 0.13/1)^1 × 1
A = 62604.18(1.13)
A = $70742.7
Her interest would be
70742.7 - 62604.18
= $8137.8
Answer:0.9c
Step-by-step explanation:
Subtract 0.1c from c
Answer:
15
Step-by-step explanation:
Prime factorization of the numbers:
330 = 2 × 3 × 5 × 11
75 = 3 × 5 × 5
450 = 2 × 3 × 3 × 5 × 5
225 = 3 × 3 × 5 × 5
LCM(330, 75, 450, 225)
= 2 × 3 × 3 × 5 × 5 × 11
= 4950
GCD(330, 75, 450, 225) = 15
Answer:
To find how tall he was at the end of the school year, you add his height at the beginning of the year and during the school year. First you should just add the inches.
2 1/4 + 7/8
The common denominator is 8.
2 2/8 + 7/8
2 9/8
3 1/8
Put back in the 5 ft.
So, Jerry was 5ft and 3 1/8 inches at the end of the school year.
Hope this helped! :)
Answer:
^algebra^
#1). a - b=4
a=4 + b .....(equation 1)
#2) a + b=12
(4 + b) + b= 12
4 + b + b=12
4 + 2b=12
2b= 12 - 4
2b =8
b= 8:2
b=4
subtituted b in equation 1
a= 4 + b
a= 4 + 4
a=8
so, the number is 8 and 4
