Question

(GEOMETRY HELP) Given right triangle JKL, what is the value of cos(L)?

Answer 1

Step 1

In the right triangle JKL

Find the value of JL

Applying the Pythagorean Theorem

$JL^{2} =JK^{2}+KL^{2}$

in this problem we have

$JK=12\ units\\KL=5\ units$

substitute the values

$JL^{2} =12^{2}+5^{2}$

$JL^{2} =169$

$JL=13\ units$

Step 2

Find the value of cos(L)

we know that

$cos(L)=\frac{adjacent\ side\ angle\ L}{hypotenuse}=\frac{KL}{JL}=\frac{5}{13}$

therefore

the answer is the option A

$cos(L)=\frac{5}{13}$

Answer 2

the answer is 5/13

this is correct on e2020