=(3a-4a-3a)+(2b+6b-2b)+(-7c+9c-7c)
=-4a+6b-5c #
Answer:
1000000
ten thousands place : 0
hundred thousands place : 10 x 0 = 0
Firstly, we need to draw triangle
we know that
O is a centroid
and centroid divides median into 2:1
so,

we have FO=4
so, we can plug it


now, we can find CF
CF=OC+FO
CF=8+4
CF=12
now, we can see triangle ACF is a right angled triangle
so, we can use pythagoras theorem

now, we can solve for x



Since, it is equilateral triangle
so,

we know that
E is a mid-point
so,

now, we can plug values

................Answer
Answer:
d=8√2 = 11.31
x=3√3 = 5.20
y=6√3 = 10.39
Step-by-step explanation:
d²=8²+8²
d²=64+64
d²=128
d=√128
d=√64*2
d=8√2 = 11.31
30-60-90 triangle
x-x√3-2x
x√3=9
x=9/√3
x=3√3
y=2x
y=2 * 3√3
y=6√3
Answer:
eccentricity; e = 1/7
k = 12
Conic section; Ellipse
Step-by-step explanation:
The first step would be to write the polar equation of the conic section in standard form by multiplying the numerator and denominator by 1/7;

The polar equation of the conic section is now in standard form;
The eccentricity is given by the coefficient of cos theta in which case this would be the value 1/7. Therefore, the eccentricity of this conic section is 1/7.
The eccentricity is clearly between 0 and 1, implying that the conic section is an Ellipse.
The value in the numerator gives the value of k; k = 12