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Alina [70]
3 years ago
11

1x+5=10 pls do it for me i'll give you brainly

Mathematics
2 answers:
yaroslaw [1]3 years ago
6 0
1x+5=10
-5. -5
1x=5

X=5
STatiana [176]3 years ago
4 0

1x+5=10

1x-5=10

x=5 that is the answer to the question hoped it helped.

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Find the sum of the polynomials.
attashe74 [19]
=(3a-4a-3a)+(2b+6b-2b)+(-7c+9c-7c)
=-4a+6b-5c #
3 0
3 years ago
Generate a number that has a digit in the hundred thousand place that is 10 times the digit in the ten thousands place.
baherus [9]

Answer:

1000000

ten thousands place : 0

hundred thousands place : 10 x 0 = 0

3 0
3 years ago
In equilateral ΔABC, AD, BE, and CF are medians. If FO = 4, then AE = A) 4 B) 4 3 C) 8 D) 12
vampirchik [111]

Firstly, we need to draw triangle

we know that

O is a centroid

and centroid divides median into 2:1

so,

\frac{CO}{FO} =\frac{2}{1}

we have FO=4

so, we can plug it

\frac{CO}{4} =\frac{2}{1}

CO=8

now, we can find CF

CF=OC+FO

CF=8+4

CF=12

now, we can see triangle ACF is a right angled triangle

so, we can use pythagoras theorem

x^2=(\frac{x}{2} )^2+12^2

now, we can solve for x

\frac{3x^2}{4}=144

x^2=192

x=8\sqrt{3}

Since, it is equilateral triangle

so,

AC=x=8\sqrt{3}

we know that

E is a mid-point

so,

AE=\frac{AC}{2}

now, we can plug values

AE=\frac{8\sqrt{3}}{2}

AE=4\sqrt{3}................Answer


5 0
3 years ago
Read 2 more answers
Find the value of the variables.
Ksju [112]

Answer:

d=8√2 = 11.31

x=3√3 = 5.20

y=6√3 = 10.39

Step-by-step explanation:

d²=8²+8²

d²=64+64

d²=128

d=√128

d=√64*2

d=8√2 = 11.31

30-60-90 triangle

x-x√3-2x

x√3=9

x=9/√3

x=3√3

y=2x

y=2 * 3√3

y=6√3

5 0
2 years ago
Q9: Determine e, k, and identify the type of conic for r= 12/7-cos theta .
lapo4ka [179]

Answer:

eccentricity; e = 1/7

k = 12

Conic section; Ellipse

Step-by-step explanation:

The first step would be to write the polar equation of the conic section in standard form by multiplying the numerator and denominator by 1/7;

r=\frac{\frac{12}{7} }{1-\frac{1}{7}cos theta}

The polar equation of the conic section is now in standard form;

The eccentricity is given by the coefficient of cos theta in which case this would be the value 1/7. Therefore, the eccentricity of this conic section is 1/7.

The eccentricity is clearly between 0 and 1, implying that the conic section is an Ellipse.

The value in the numerator gives the value of k; k = 12

3 0
3 years ago
Read 2 more answers
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