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2 years ago

Please help i am super confused and it is worth a lot of points !!!! Find the measure of

Mathematics

1 answer:

garri49 [273]2 years ago

3 0

Answer:

its probably around 110* or 100

Step-by-step explanation:

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Lillie Manson paid for tuition at a summer school with an installment loan of $3,600 at 9% interest for 12 months. Her monthly p

gizmo_the_mogwai [7]

After 6 months, ammount left to pay = $1,840.34
On the seventh month, he payed of the debt with the interest (for one month).
Amount paid off at the seventh month = 1840.34(1 + 0.09/12) = 1840.34(1.0075) = 1854.14

Amount to have paid in the remaining 6 months = 314.83 x 6 = 1888.98
Amount saved = 1888.98 - 1854.14 = $34.84

7 0

3 years ago

A quadrilateral with two sets of parallel lines is

Rufina [12.5K]

The answer is a square

8 0

3 years ago

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P(a number greater than 3 and C

slamgirl [31]

Answer: uhhhh 4

Step-by-step explanation:

3 4 c d

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3 years ago

Can someone help me please :)

Airida [17]

Answer:

C) 3/2

Step-by-step explanation:

$- 3x + 2y = 4 \\ 2y = 3x + 4 \\ y = \frac{3}{2} x + 2 \\ y = mx + b \\ m = \frac{3}{2}$

I hope that is useful for you :)

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2 years ago

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The spherical balloon is inflated at the rate of 10 m³/sec. Find the rate at which the surface area is increasing when the radiu

rjkz [21]

The balloon has a volume $V$ dependent on its radius $r$ :

$V(r)=\dfrac43\pi r^3$

Differentiating with respect to time $t$ gives

$\dfrac{\mathrm dV}{\mathrm dt}=4\pi r^2\dfrac{\mathrm dr}{\mathrm dt}$

If the volume is increasing at a rate of 10 cubic m/s, then at the moment the radius is 3 m, it is increasing at a rate of

$10\dfrac{\mathrm m^3}{\mathrm s}=4\pi (3\,\mathrm m)^2\dfrac{\mathrm dr}{\mathrm dt}\implies\dfrac{\mathrm dr}{\mathrm dt}=\dfrac5{18\pi}\dfrac{\rm m}{\rm s}$

The surface area of the balloon is

$S(r)=4\pi r^2$

and differentiating gives

$\dfrac{\mathrm dS}{\mathrm dt}=8\pi r\dfrac{\mathrm dr}{\mathrm dt}$

so that at the moment the radius is 3 m, its area is increasing at a rate of

$\dfrac{\mathrm dS}{\mathrm dt}=8\pi(3\,\mathrm m)\left(\dfrac5{18\pi}\dfrac{\rm m}{\rm s}\right)=\dfrac{20}3\dfrac{\mathrm m^2}{\rm s}$

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2 years ago