Answer:it depicts asexual reproduction occurring through binary fission, a process that does not lead to genetic variation
Explanation:
Answer: alleles
Explanation:
Alleles are different forms of a given gene. Alleles are mutated forms of a given gene which controls a particular trait. For instance, the gene that codes for hemoglobin is denoted with the letter A but the gene has another variant denoted by S. In abnormal hemoglobin S (sickle hemoglobin), glutamate is replaced by valine at position 6 in the amino acid sequence of the two beta chains of hemoglobin. This change in the amino acid sequence causes the red blood cells to have a sickle shape resulting in sickle cell disease. Therefore hemoglobin A and S are alleles of a given gene.
Let's call the colour alleles C for dominant purple, and c for recessive white.
We have crossed Cc with Cc. So if we put that in a Punnett square, we'd have a CC, two Cc and a cc. That would give us a 3:1 ratio of purple to white, so you'd expect 15 purple and 5 white flowers. :)
Answer: Always and always
Explanation:
Within any large animal population there is always a variety of traits seen in the population. When there is a large number of individuals in a population then there are chances that there a genetic diversity.
Sexual reproduction in the organism can lead to the genetic variation in the organism. There are chances to have more variation in the population having more organism.
Two different organism are genetically different and there are variety of traits seen in the two animals that belongs to different species.
Answer:
<h2>(14+16)/1000 *100= 3</h2>
Explanation:
Parental combinations are always more common then other recombinant progenies.
A female fly is heterozygous for three X-linked genes crossed with an abc/Y male. . If single crossover occurs between a & b and between b & c, then the double cross is that, which occurs in both.
Double cross over progeny are always least in number, so here double cross occurs are in abC 14 and ABc 16.
So we are expecting that number of double cross over progeny= (14+16)/1000 *100= 3
