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Ierofanga [76]
3 years ago
12

What is the area of parallelogram ABCD?

Mathematics
2 answers:
prisoha [69]3 years ago
3 0

Answer:13 square units

Step-by-step explanation:

I j took the test and thirteen was right :)

irina [24]3 years ago
3 0

Answer:

13 square units

Step-by-step explanation:

You might be interested in
How many pints and in a cup??
sergey [27]

Answer:

.5

Step-by-step explanation:

because a pint is 2 cups so divide by 4  because you multiply that 2 by another 2 is 4 so once you do that its .5

4 0
2 years ago
If why varies with the square of x and Y equals 24 when x equals 10 then the constant of proportionality is ____, and the value
Dennis_Churaev [7]

Answer:

Step-by-step explanation:

y varies with the square of x:

y = kx²

y equals 24 when x equals 10

24 = k·10²

constant of proportionality k = 0.24

when x = 20, y = 0.24·20² = 96

"select two answers"  —where are the choices?

5 0
3 years ago
Please help me, thank you.
jeka94
I think its C............. :) I'm sorry if I got it wrong
6 0
2 years ago
■.Given angle TUV and ray UW, if m/TUV = 89,
aniked [119]

The measure of m<WUV is 53 degrees

<h3>Lines and angles</h3>

Given the following parameters

m<TUW = 22 +7x,

m<WUV = 41+ 6x

m<TUV. = 89

The related expression is given as:

m<TUV + m<WUV = m<TUV.

Substitute

22+7x+41+6x = 89

63 + 13x = 89

13x = 89 - 63

13x = 26

x = 2

Determine the measure of m<WUV

m<WUV = 41 + 6(2)

m<WUV = 41 + 12

m<WUV =53 degrees

Hence the measure of m<WUV is 53 degrees

Learn more on line and angles here: brainly.com/question/25770607

#SPJ1

6 0
1 year ago
Point A is located at (-4, -13). Point B is located at (-4, 3). What is the distance between point A
12345 [234]

Answer:

the distance is 16

Step-by-step explanation:

Hi there!

We are given point A (-4,-13) and point B (-4,3). We need to find the distance between those two points

the distance formula is given as \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2} where (x_{1},y_{1}) and (x_{2}, y_{2}) are points

we are given 2 points, which is what we need for the formula. However, let's label the values of the points to avoid any confusion

x_{1}=-4

y_{1}=-13

x_{2}=-4

y_{2}=3

now substitute those values into the formula. Remember: the formula uses SUBTRACTION.

\sqrt{(-4--4)^2+(3--13)^2}

simplify

\sqrt{(-4+4)^2+(3+13)^2}

now add the values inside the parenthesis that are under the radical

\sqrt{(0)^2+(16)^2}

raise everything under the radical to the second power

\sqrt{0+256}

add under the radical

\sqrt{256}

now take the square root of 256

\sqrt{256}=16

so the distance between point A and point B is <u>16</u>

Hope this helps! :)

8 0
3 years ago
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