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Sauron [17]
3 years ago
14

the movie theater collecyed $5,274 in tickets sales on eusday. if each ticket cost $9.00 .how many tickets did they sell

Mathematics
2 answers:
slamgirl [31]3 years ago
7 0
586 tickets because you need to divide 5274/9
klasskru [66]3 years ago
5 0
First Divide

5,274 by 9

Then you find the number

583

Lastly

They sold 583 tickets on Tuesday
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PLEASE HELP SUPER EASY!!!
Effectus [21]

A1. 12 i.e option D

A2. 3n-7 i.e option A

A3. -6n+20 i.e option D

A4. -70 i.e option C

Step-by-step explanation:

aₙ = a₁ + (n - 1) × d  

aₙ = the nᵗʰ term in the sequence

a₁ = the first term in the sequence

d = the common difference between terms

Using the above formula to solve the first part, we have :

  • -8 = a₁ + (2-1) × 5
  • -13 = a₁
  • a₆ = -13 + (6-1) × 5
  • a₆ = 12

For the second part, we have :

  • aₙ = -4 + (n-1)×3
  • aₙ = -4 + 3n -3
  • aₙ = 3n-7

For the third part, we have :

  • a₁=14 ; d=-6
  • aₙ = 14 + (n-1)×(-6)
  • aₙ = -6n + 20

For the fourth part, we have :

  • aₙ = 14 + (15-1)×(-6)
  • aₙ = -70
7 0
3 years ago
What is the volume in cubic inches of the right rectangular prism with a length of 5 inches a width of 8 inches, and a height of
Karo-lina-s [1.5K]

Answer:

800 in^{2}

Step-by-step explanation:

Volume = lwh

3 0
4 years ago
Read 2 more answers
zoe wrote 3/5 of her essay in 30 minutes. assuming she wrote the paper at a constant rate the entire time, which expression can
vodomira [7]
3/5 in 30 mins, 5*30=150, then she would write 3/150 or 1/50 each minute
6 0
3 years ago
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Paguei 74,00 por uma bolsa e uma sandália. A bolsa foi 23,00 mais barato q a sandália. Qual o preço da sandália?
alukav5142 [94]

Responda:

48,5

Explicação passo a passo:

Dado que:

Custo total de bolsa e sandália = 74,00

Deixei :

Custo da sandália = x

Custo da bolsa = x - 23

Preço da sandália:

x + (x - 23) = 74

x + x - 23 = 74

2x - 23 = 74

2x = 74 + 23

2x = 97

x = 97/2

x = 48,5

Portanto, custo da sandália, x = 48,5

7 0
3 years ago
the pitch, or frequency, of a vibrating string varies directly with the square root of the tension. if a string vibrates at a fr
Naily [24]
\bf \qquad \qquad \textit{direct proportional variation}\\\\
\textit{\underline{y} varies directly with \underline{x}}\qquad \qquad  y=kx\impliedby 
\begin{array}{llll}
k=constant\ of\\
\qquad  variation
\end{array}\\\\
-------------------------------\\\\
\begin{array}{llll}
\stackrel{frequency}{f}\textit{ of a vibrating string varies directly}\\
\qquad \qquad \textit{with the square root of the tension }\stackrel{tension}{t}
\end{array}

\bf f=k\sqrt{t}\quad \textit{we also know that }
\begin{cases}
f=300\\
t=8
\end{cases}\implies 300=k\sqrt{8}
\\\\\\
\cfrac{300}{\sqrt{8}}=k\implies \cfrac{300}{\sqrt{2^2\cdot 2}}=k\implies \cfrac{300}{2\sqrt{2}}=k\implies \cfrac{150}{\sqrt{2}}=k
\\\\\\
\textit{and we can \underline{rationalize} it to }\cfrac{150\sqrt{2}}{2}\implies 75\sqrt{2}=k

\bf thus\qquad f=\stackrel{k}{75\sqrt{2}}\sqrt{t}\implies \boxed{f=75\sqrt{2t}}\\\\
-------------------------------\\\\
\textit{now, when t = 72, what is \underline{f}?}\qquad f=75\sqrt{2(72)}
5 0
4 years ago
Read 2 more answers
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