Consecutive odd numbers are 2 apart
they are
x,x+2,x+4,x+6
10+2x=x+4+x+6
10+2x=2x+10
x=x
true
any consecutive odd integers will work
1,3,5,7 works
3,5,7,9 works
etc
Step-by-step explanation:
no. of players = 22/3 = 7 remainder 1
therefore, 7 people can play, and 1 card remaining
Answer: no it shouldn’t
Step-by-step explanation:
108 = ( x)(48-x)
108 = 48x - x^2
48x -x^2 -108 = 0
I'm assuming you're doing solve the square right now, so you should be able to do the rest.