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sveticcg [70]
3 years ago
15

The perimeter of the rectangle below is 74 units. Find the length of side RS

Mathematics
2 answers:
Goryan [66]3 years ago
6 0
The answer is 28 if you use the method I used

Alika [10]3 years ago
4 0

Answer:

20 units

Step-by-step explanation:

The perimeter of a rectangle is

P = 2(l+w)

P = 2( 3x+2 + 4x)

Adding like terms

P = 2( 7x+2)

We know the perimeter is 74 units

74 = 2 ( 7x+2)

Divide by 2

74/2 = 2/2 (7x+2)

37 = 7x+2

Subtract 2 from each side

37-2 = 7x+2-2

35 = 7x

Divide by 7

35/7 = 7x/7

5 =x

We want to find the length RS = PQ = 4x

RS = 4x = 4*5 = 20

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Solve and graph this inequality <br> -6&lt;2x-4&lt;12
vampirchik [111]

Answer:

-1 ≤ x ≤8 (don't care about the equal sign)

Step-by-step explanation:

-6+4≤2x≤12+4

=-2≤2x≤16

=-1≤x≤8

7 0
3 years ago
(TIME SENSITIVE PLEASE HELP) Use matrices to determine the coordinates of the vertices of the reflected figure. Then graph the p
Len [333]

The matrix R represents the reflection matrix for the provided vertices, and graph A represents the pre-image and the image on the same coordinate grid.

<h3>What is the matrix?</h3>

It is defined as the group of numerical data, functions, and complex numbers in a specific way such that the representation array looks like a square, rectangle shape.

We have vertices shown in the picture.

Form a matrix using the vertices:

= \left[\begin{array}{ccc}-3&5&6\\7&3&-5\\\end{array}\right]

To reflect over the x-axis, multiply by the reflection matrix:

= \left[\begin{array}{ccc}1&0\\0&-1\\\end{array}\right]\left[\begin{array}{ccc}-3&5&6\\7&3&-5\\\end{array}\right]

\rm R=  \left[\begin{array}{ccc}-3&5&6\\-7&-3&5\\\end{array}\right]

The above matrix represent the reflection matrix.

Thus, the matrices R represents the reflection matrix for the provided vertices, and graph A represents the pre-image and the image on the same coordinate grid.

Learn more about the matrix here:

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4 0
2 years ago
Can someone please help me!?!?!?
sineoko [7]

3. Alt. Interior Angles

4. definition of midpoint

5 0
3 years ago
A university found that 20% of its students withdraw without completing the introductory statistics course. Assume that 20 stude
bulgar [2K]

Answer:

a) 20.61%

b) 21.82%

c) 42.36%

d) 4 withdrawals

Step-by-step explanation:

This situation can be modeled with a binomial distribution, where p = probability of “success” (completing the course) equals 80%  = 0.8 and the probability of “failure” (withdrawing) equals 0.2.

So, the probability of exactly k withdrawals in 20 cases is given by

\large P(20;k)=\binom{20}{k}(0.2)^k(0.8)^{20-k}

a)

We are looking for

P(0;20)+P(0;1)+P(0;2) =  

\large \binom{20}{0}(0.2)^0(0.8)^{20}+\binom{20}{1}(0.2)^1(0.8)^{19}+\binom{20}{2}(0.2)^2(0.8)^{18}=

0.0115292150460685 + 0.0576460752303424 + 0.136909428672063 = 0.206084718948474≅ 0.2061 or 20.61%

b)

Here we want P(20;4)

\large P(20;4)=\binom{20}{4}(0.2)^4(0.8)^{16}=0.218199402\approx 0.2182=21.82\%

c)

Here we need

\large \sum_{k=4}^{20}P(20;k)=1-\sum_{k=1}^{3}P(20;k)

But we already have P(0;20)+P(0;1)+P(0;2) =0.2061 and

\large \sum_{k=1}^{3}P(20;k)=0.2061+P(20;3)=0.2061+0.205364 \approx 0.4236=42.36\%

d)

For a binomial distribution the <em>expectance </em>of “succeses” in n trials is np where p is the probability of “succes”, and the expectance of “failures” is nq, so the expectance for withdrawals in 20 students is 20*0.2 = <em>4 withdrawals.</em>

3 0
3 years ago
Describe how to determine the average rate of change between x=1 and x=3 for the function f(x)=3x^3+1. Include the average rate
icang [17]

Answer:

39.

Step-by-step explanation:

We subtract  f(1) which is the value of f(x) when x = 1 from f(3),  then we divide by 3 - 1.

It is [(f3) - f(1]) / (3 - 1), so

Average rate of change = (3(3)^3 + 1) - (3(1)^3 + 1) / (3 - 1)

= (82 - 4) / 2

= 78 / 2

=  39.

7 0
4 years ago
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