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2 years ago

What is the value of 138+(20-15)

Mathematics

2 answers:

iVinArrow [24]2 years ago

8 0

The answer is 133 so why u just add 138 with 20 and then u will subtract 15.

schepotkina [342]2 years ago

4 0

Well since 20-15 equals 5...

The equation is now 138-5, which is 133.

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Is b a linear combination of a1, a2, and a3?

salantis [7]

A1 = (1, -2 , 0) ; a2 = (0,1,2) ; a3 = (5,-6,8) ; b = (2,-1,6)

2*a1 = (2, -4,0)
3*a2 = (0, 3, 6)
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sum = (2, -1, 6) = b

Hope this helps

3 0

3 years ago

Need help! Does anyone know how to do this type of math? (It's geometry)

mart [117]

Answer:

Step-by-step explanation:

refer the attachment

to solve the question we need to recall one of the most important theorem of circle known as two tangent theorem which states that tangents which meet at the same point are equal that is being said

FA=AI=17
CH=CG=2.5

since $\rm BA=FA+FB$ and it's given that FA and BA are 17 and 29 FB should be

$\rm 29=17+FB$

therefore,

$FB=29-17=\boxed{12}$

once again by two tangent theorem we acquire:

$FB=BH=\boxed{12}$

As BC=BH+CH,BC is

12+2.5
$\boxed{14.5}$

likewise,AD=AI+DI so,

21=17+DI [AD=21(given) and AI=17 (by the theorem)]

thus,

DI=21-17= $\boxed{4}$

By the theorem we obtain:

DI=DG=4

Similarly,DC=DG+CH therefore,

DC=4+2.5= $\boxed{6.5}$

Now finding the Perimeter of ABCD

$P_{\text{ABCD}}=\text{AB+AD+BC+DC}$

substitute what we have and got

$P_{\text{ABCD}}=\text{29+21+14.5+6.5}$

simplify addition:

$P_{\text{ABCD}}=\boxed{71}$

hence,

the Perimeter of ABCD is 71

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Step-by-step explanation:

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