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3 years ago

41 tens×4hundreds= 410×400=

Mathematics

1 answer:

weqwewe [10]3 years ago

7 0

410x400 is correct and your answer would be 164,000.

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Determine if each relation is a function

Archy [21]

No; you can not have an x-value go to more than one y-value

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2 years ago

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Determine the number of possible triangles, ABC, that can be formed given angle A = 30°, a = 4, and b = 6.

Sophie [7]

Answer:

Step-by-step explanation:

Alright, lets get started.

using Sine Law,

$\frac{sinA}{a}=\frac{sinB}{b}$

$\frac{sin30}{4}=\frac{sinB}{6}$

$sinB=0.75$

$angle B = 48.6$

Another angle will be

$angle B' = 180-48.6 = 131.4$

considering angle B, angle C = $180 - (48.6+30)=101.4$

considering angle B', angle C' = $180-(131.4+30)=18.6$

$\frac{sinA}{a}=\frac{sinC}{c}$

$\frac{sin30}{4}=\frac{sin101.4}{c}$

$c = 7.84$

Similarly, finding c'

$\frac{sinA}{a}=\frac{sinC'}{c'}$

$\frac{sin30}{4}=\frac{sin18.6}{c'}$

$c'=2.55$

Hence two triangles are possible with below details: : Answer

A = 30, B = 48.6, C = 101.4, c = 7.84

A = 30, B' = 131.4, C' = 18.6, c' = 2.55

Hope it will help :)

5 0

2 years ago

On the following number line, two rational numbers are graphed.Represent the two numbers as fractions (or mixed numbers) in lowe

nordsb [41]

The first graphed rational number is at the middle of -2 and -1, thus the number represented is $-1 \frac{1}{2}$

The second graphed number is five out of six places from from 0 to 1, thus the number graphed is $0+ \frac{5}{6} = \frac{5}{6}$

The difference between the two numbers can be represented as
$-1 \frac{1}{2} - \frac{5}{6}$
or
$\frac{5}{6} -(-1 \frac{1}{2} )= \frac{5}{6} +1 \frac{1}{2}$

To find the difference,

$-1 \frac{1}{2} - \frac{5}{6} \\ \\ =-1 \frac{3+5}{6} \\ \\ =-1 \frac{8}{6} =-2 \frac{2}{6} \\ \\ =-2 \frac{1}{3}$

Also,

$\frac{5}{6} +1 \frac{1}{2} \\ \\ =1 \frac{5+3}{6} \\ \\ =1 \frac{8}{6} =2 \frac{2}{6} \\ \\ =2 \frac{1}{6}$

4 0

3 years ago

If t >0 and t^2-4=0 What is the value of t?

Maslowich

T=2
t^2=4
4-4=0
is that right?

6 0

3 years ago

7. Solve each equation.

Firlakuza [10]

Answer:

answer is in the picture

4 0

2 years ago