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scoundrel [369]
3 years ago
15

Solve for a p=w/a A. a=pw B.a=p/w C.a=w/p D.a=w+p

Mathematics
1 answer:
Debora [2.8K]3 years ago
4 0

Answer:

answer is a = w/p

Step-by-step explanation:

p = w/a

pa = w

a = w/p

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5. The number −6 is 2 more than an unknown number. Find the unknown number.
Mariana [72]

Answer:

-4

Step-by-step explanation:

-6 - 2 = -4

3 0
3 years ago
A psychological experiment was conducted to investigate the length of time (time delay) between the administration of a stimulus
aleksklad [387]

Answer:

The P-value of this sample is 0 and is less than the significance level (0.05), so the effect is significant and the null hypothesis is rejected.

As there is significant evidence to reject H_0: \mu= 1.6, we can say that there is significant evidence to claim that the mean time delay for the hypothetical population of all persons who may be subjected to the stimulus differs from 1.6 seconds.

The significance level for this test is 0.05.

Step-by-step explanation:

In this case, we want to prove if there is significant evidence that the mean differs from 1.6 seconds. That is the same as having evidence to reject the the hypothesis H_0:\mu= 1.6 (the null hypothesis always have the equal sign).

We have to test the null hypothesis

H_0:\mu= 1.6

The significance level for this test is 0.05

Calculation of the t-statistic:

t=\frac{M-\mu}{s/\sqrt{n}} =\frac{2.2-1.6}{0.57/\sqrt{36}} =\frac{0.6}{0.063}= 9.47

If we look up in a t-table for t=9.47 and df=(36-1)=35, we get this value appears with a probability of zero. A large number like that is very unlikely to happen.

The P-value of this sample is 0 and is less than the significance level (0.05), so the effect is significant and the null hypothesis is rejected.

As there is significant evidence to reject H_0: \mu= 1.6, we can say that there is significant evidence to claim that the mean time delay for the hypothetical population of all persons who may be subjected to the stimulus differs from 1.6 seconds.

6 0
3 years ago
Carbon dioxide comprises approximately what percentage of the atmosphere
In-s [12.5K]

The Carbon Dioxide in the atmosphere is only very small relative to other gases. Typically, it only consists about 0.038 percent or 0.04 percent of the gases in the atmosphere.

<span>
Even though it is only small, CO2 is very important since it is one of the greenhouse gases which ensures that the Earth stays warm.</span>

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3 years ago
J PLS HELP 8 MINUTES LEFT Ted Thumper, who bats at number eight, had an average (mean) of 14 last year. So far this year he has
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Answer:

answer is 15 and second one i dont know yet sorry am doing scoo

Step-by-step explanation:

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1 year ago
PLEASE HELP! I will give you the brainiest and A LOT of points! (Ch.5.7)
iren2701 [21]

Answer:

company A pays more, by the end of yr 10 they pay $9000 more

Step-by-step explanation:

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