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Alenkinab [10]
3 years ago
14

Find the quotient of the complex numbers. Leave answer in polar form.

Mathematics
1 answer:
kirza4 [7]3 years ago
6 0
\dfrac{z_1}{z_2}=\dfrac{\sqrt3}{\sqrt6}\left(\cos\left(\dfrac{7\pi}4-\dfrac{9\pi}4\right)+i\sin\left(\dfrac{7\pi}4-\dfrac{9\pi}4\right)\right)
\dfrac{z_1}{z_2}=\sqrt2\left(\cos\left(-\dfrac{2\pi}4\right)+i\sin\left(-\dfrac{2\pi}4\right)\right)
\dfrac{z_1}{z_2}=\sqrt2\left(\cos\left(-\dfrac\pi2\right)+i\sin\left(-\dfrac\pi2\right)\right)
\dfrac{z_1}{z_2}=\sqrt2\left(\cos\dfrac{3\pi}2+i\sin\dfrac{3\pi}2\right)
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If each dozen cost $3.70 what should be the selling price be if he wants to make an 80% profit?​
klemol [59]
Answer: $6.66

Explanation:
3.70 multiplied by 0.80 = 2.96.
3.70 + 2.96 = $6.66
7 0
3 years ago
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In the figure, the perimeter of hexagon ABCDEF is approximately
Nikitich [7]
First solve the length of side BC, CD, EF and FA   Since BC = CD = sqrt( 10^2 + 10^2) BC = CD = 14.1421  
FA = EF = sqrt(10^2 + 20^2) = 23.3607  
So the perimeter = 10 + 10 + 14.1421 + 14.1421 + 23.3607 = 93

The area is made up be triangle FAE, rectangle ABDE and triangle BCD
A = 0.5(20)(20) + (10)(20) + 0.5(20)(10)
<span>A = 500 sq units</span>
7 0
3 years ago
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One pound of swordfish costs as much as 1.5 pounds of salmon. Mrs. O pays $39 for 2 pounds of salmon and 3 pounds of swordfish.
Dimas [21]

Answer:

The ratio of the amount for swordfish to the amount of salmon is 6:4

Step-by-step explanation:

Given as :

The price for 1 pound of swordfish = The price of 1.5 pound of salmon

So, On this relation

The price for ( 1 × 2 ) pound of swordfish = The price of ( 1.5× 2 )  pound of salmon

i.e The price for 2 pound of swordfish = The price of 3 pound of salmon

Now According to question

Mrs. O pay the total money for 2 pounds of swordfish and 3 pound of salmon = $ 39

Let the money she pay for swordfish = 2 sw

And The money she pay for salmon = 3 sa

∵, The total money she pay for both  = $ 39

I.e  2 sw + 3 sa = 39

As 2 sw = 3 sa

So, 3 sa + 3 sa = 39

Or, 6 sa = 39

or, sa = \frac{39}{6} = \frac{13}{2}

∴ sw = \frac{13}{2} × \frac{3}{2}

or, sw = \frac{39}{4}

Now, the ratio of the amount for swordfish to the amount of salmon = \frac{\frac{39}{4}}{\frac{13}{2}}

I.e The ratio = \frac{6}{4}

Hence The ratio of the amount for swordfish to the amount of salmon is 6:4

Answer

3 0
3 years ago
Find the sixth term in the following arithmetic sequence.<br> 1/4 , 1/8 ,0...
Shtirlitz [24]

Answer: 3/8

1/4 + 1/8 divided by 2

3 0
3 years ago
What is the sum of the first five terms of a geometric series with A1 equals 20 and R equals 1/4
sweet-ann [11.9K]
Sum = 20(1-(1/4)^5) / (1-1/4) = 26.64
6 0
3 years ago
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