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juin [17]
3 years ago
11

A box contains 48 snack-sized bags of popcorn.

Mathematics
1 answer:
Svetlanka [38]3 years ago
4 0

Answer:

0.625 ounces

Step-by-step explanation:

since the box weighs 5 ounces you subtract 5 from the total and divide 48 by 30

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, list the first five terms of each sequence.<br> f(n + 1) = −2f(n) + 8 and f(1) = 1 for n ≥ 1
svet-max [94.6K]

Answer: 1, 7, 1, 7, 1.

Step-by-step explanation:

The given function :  f(n+1)=-2f(n)+8 and  f(1) = 1 for n ≥ 1

We put value of n=1,2,3,4 , we get

For n=1  , f(2)=f(1+1)=-2f(1)+8=-1(1)+8=-1+8=7

For n=2  , f(3)=f(2+1)=-2f(2)+8=-1(7)+8=1

For n=3  , f(4)=f(3+1)=-2f(3)+8=-1(1)+8=7

For n=4  , f(5)=f(4+1)=-2f(4)+8=-1(7)+8=1

Hence, the  first five terms of the given sequence are 1, 7, 1, 7, 1.

7 0
3 years ago
you invest $4000 in an account that pays simple interest of 4% for 10 years. how much will you have in 10 years?
bulgar [2K]
Annual interest - 4%

interest in 1 year 
(4/100) * 4000
160

interest in 10 years
160 * 10
1600

So the amount you have at the end of 10 years
4000 + 1600
$ 5600
4 0
3 years ago
Read 2 more answers
4 and 2/3 divided by 3/4 as a fraction
Bumek [7]

Answer:

dg

Step-by-step explanation:

7 0
2 years ago
Express the fraction in simplest form. 2/8
seropon [69]
It will be 1/4.
That is your answer. 
Hope this helps

5 0
3 years ago
Read 2 more answers
Let g(x) = 2x and h(x)= x^2 -4. find (g o h)(0)
finlep [7]
The answer is -8

====================================================

Explanation:

There are two ways to get this answer

Method 1 will have us plug x = 0 into h(x) to get
h(x) = x^2 - 4
h(0) = 0^2 - 4
h(0) = 0 - 4
h(0) = -4
Then this output is plugged into g(x) to get
g(x) = 2x
g(-4) = 2*(-4)
g(-4) = -8 which is the answer
This works because (g o h)(0) is the same as g(h(0)). Note how h(0) is replaced with -4
So effectively g(h(0)) = -8 which is the same as (g o h)(0) = -8

-----------------------

The second method involves a bit algebra first
Start with the outer function g(x). Then replace every x with h(x). On the right side, we will replace h(x) with x^2-4 because h(x) = x^2-4

g(x) = 2x
g(x) = 2( x )
g(h(x)) = 2( h(x) ) ... replace every x with h(x)
g(h(x)) = 2( x^2-4 ) ... replace h(x) on the right side with x^2-4
g(h(x)) = 2x^2-8
(g o h)(x) = 2x^2-8

Now plug in x = 0
(g o h)(x) = 2x^2-8
(g o h)(0) = 2(0)^2-8
(g o h)(0) = 2(0)-8
(g o h)(0) = 0-8
(g o h)(0) = -8

Regardless of which method you use, the answer is -8

5 0
3 years ago
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