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Agata [3.3K]
3 years ago
5

Part 1: Using complete sentences, compare the key features and graphs of sine and cosine. What are their similarities and differ

ences?
Part 2: Using these similarities and differences, how would you transform f(x) = 2 sin(2x - π) + 3 into a cosine function in the form f(x) = a cos(bx - c) + d? (10 points)
Mathematics
1 answer:
vodomira [7]3 years ago
6 0
1/2 convert the following fractions to percents
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Could someone please explain how to do these!
san4es73 [151]
Soh cah toa is your best friend in trig

sin(x) = opposite/hypotenuse
cos(x) = adjacent/hypotenuse
tan(x) = opposite/adjacent

X is opposite from 43 degrees.
16 is the hypotenuse because it’s the longest side.

We need to use sin(x) because we’re given the opposite/hypotenuse ratio.

For sin(x) plug in the angle for x:

sin(43) = X/16
Multiply both sides by 16.

X = 16*sin(43)
You can plug it into your calculator.
8 0
3 years ago
Compare 3.277 and 3.274. Starting at the left, look for the first place where the digits are different. What place is it?
Lady_Fox [76]
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Tenths place because the two numbers that are different in both numbers in the same place are the 7 and the 4. Both in the tenths place.
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5 0
3 years ago
Read 2 more answers
What is the vertex form of the quadratic equation represented on the table?
sergeinik [125]

Check the picture below, so the parabola looks more or less like so, hmmm with a vertex at (-1 , -4), so, using those values from the table

~~~~~~\textit{vertical parabola vertex form} \\\\ y=a(x- h)^2+ k\qquad \begin{cases} \stackrel{vertex}{(h,k)}\\\\ \stackrel{"a"~is~negative}{op ens~\cap}\qquad \stackrel{"a"~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}

\stackrel{vertex}{\stackrel{h}{-1}~~,~~\stackrel{k}{-4}}\qquad \implies y=a[x-(-1)]^2-4\implies y=a(x+1)^2-4 \\\\\\ \textit{we also know that} \begin{cases} x=2\\ y=14 \end{cases}\implies 14=a(2+1)^2-4\implies 18=9a \\\\\\ \cfrac{18}{9}=a\implies 2=a~\hspace{10em}\boxed{y=2(x+1)^2-4}

7 0
2 years ago
33 students in a math class took their chapter test, and 25 of these students passed their test. What percent of students failed
Andrews [41]

25 out of 33 passed the test.

Lets see how many failed,

33-25 = 8

Now lets take out the percentage which basically will be

8÷33×100= 24.4%

4 0
4 years ago
Y= x^3 + 8x^2 +5x<br> work out the coordinates of the two turning points
aliya0001 [1]

Answer:

(-5, 50) and (-1/3, -0.815)

Step-by-step explanation:

The equation is;

y = x³ + 8x² + 5x

Now the turning point will occur at where dy/dx = 0.

Thus;

dy/dx = 3x² + 16x + 5

At dy/dx = 0, we have;

3x² + 16x + 5 = 0

From quadratic formula, we can get;

x = -5 or -⅓

Thus, let's find y at this points.

y = -5³ + 8(-5)² + 5(-5)

y = -125 + 200 - 25

y = 50

Also,at x = -⅓, we have;.

y = (-⅓)³ + 8(-⅓)² + 5(-⅓)

y = -1/27 + 8/9 - 5/3

y = -0.815

Thus,the coordinates of the turning points are;

(-5, 50) and (-1/3, -0.815)

6 0
3 years ago
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