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Vesna [10]
3 years ago
11

Help me please asap!!!!1

Mathematics
2 answers:
pantera1 [17]3 years ago
8 0
Hmm to be honest I do t really know I just need points
4vir4ik [10]3 years ago
4 0
I think if you reverse it it’ll be the same and equal the same thing
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Plz help me with this
Nana76 [90]
This question is not even trying to test your arithmetic.  It's just testing
to see whether you know how to read numbers in words properly.

When you read numbers in words, the only time you ever say "and"
is for a decimal point.  There are no decimals in this question, so the
"and" is not a part of any numbers.

The question gives you two numbers. The word "and" is the marker
that's BETWEEN them.  The two numbers are 1,300 and 950 .

The first thing the question wants you to do is write the numerical
expression for all the words.  That's    (1300 - 950) / 4 .

The next thing you're supposed to do is"evaluate the expression" ...
find out what number it all boils down to.  I don't think you'll have
any trouble with that now.
3 0
3 years ago
Whats 45 times 25 to the power of 3 minus 12 divided by 9
atroni [7]
I got 703,124 rounded.
6 0
3 years ago
14. What point is in the first quadrant?<br> a. (1,-2)<br> b. (-2.1)<br> C (1,2)<br> d. (-2,-1)
Viefleur [7K]
Mf- we need a picture
4 0
3 years ago
The point (5,-1) is a solution of the equation:y=2x-11<br><br>true or false​
irakobra [83]

Answer:

True

Step-by-step explanation:

6 0
4 years ago
Solve for x, 0 ≤ x ≤2π (2cosx-1)(2sinx+√3 ) = 0
vladimir1956 [14]

Answer:

x = π/3, x = 5π/3, x = 4π/3

Step-by-step explanation:

Let's split the given equation (2cosx-1)(2sinx+√3 ) = 0 into two parts, and solve each separately. These parts would be 2cos(x) - 1 = 0, and 2sin(x) + √3  = 0.

2\cos \left(x\right)-1=0,\\2\cos \left(x\right)=1,\\\cos \left(x\right)=\frac{1}{2}

Remember that the general solutions for cos(x) = 1/2 are x = π/3 + 2πn and x = 5π/3 + 2πn. In this case we are given the interval 0 ≤ x ≤2π, and therefore x = π/3, and x = 5π/3.

Similarly:

\:2\sin \left(x\right)+\sqrt{3}=0,\\2\sin \left(x\right)=-\sqrt{3},\\\sin \left(x\right)=-\frac{\sqrt{3}}{2}

The general solutions for sin(x) = - √3/2 are x = 4π/3 + 2πn and x = 5π/3 + 2πn. Therefore x = 4π/3 and x = 5π/3 in this case.

So we have x = π/3, x = 5π/3, and x = 4π/3 as our solutions.

5 0
3 years ago
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