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Dmitrij [34]
3 years ago
11

−2x = 4y + 6 2(2y + 3) = 3x − 5 What is the solution (x, y) to the system of equations above

Mathematics
1 answer:
Wewaii [24]3 years ago
6 0

Answer:

(1;-2)

Step-by-step explanation:

x=-2y-3

2(2y+3)=-6y-9-5

10y=-20

y=-2

x=4-3=1

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X ^ 3 - 2x squared - 23x + 60
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If the question is the best way to factor it I would say: (x-4)(x-3)(x+5)

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3 years ago
A rectangle has a height of 6k3 and a width of 2k2 + 4k +5.
Trava [24]

Answer: 12k^5+24k^4+30k^3

Step-by-step explanation:

Given : The height of the rectangle = 6k^3

The width of the rectangle = 2k^2+4k+5

Formula : Area = height x width

Therefore , the area of triangle in terms of polynomial will be :

6k^3\times( 2k^2+4k+5)\\\\= 6k^3(2k^2)+6k^3(4k)+6k^3(5)\ \ [\text{Using Distributive property}]\\\\=12k^{3+2}+24k^{3+1}+30k^3\ \ [\text{Using exponents rule}:\ a^n\times a^m=a^{n+m}]\\\\=12k^5+24k^4+30k^3

Hence, the area of the entire rectangle =12k^5+24k^4+30k^3

5 0
4 years ago
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Tems11 [23]

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5 0
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3 years ago
Read 2 more answers
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Veronika [31]

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Step-by-step explanation:

[tex] \frac{ \sqrt{3} }{2} + \frac{ \sqrt{3} }{2} \\ \\ \frac{2 \sqrt{3} + 2 \sqrt{3} }{4} \\ \frac{4 \sqrt{3} }{4 } \\ \sqrt{3} [tex]

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