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miskamm [114]
3 years ago
6

Someone came into a store and stole 100 dollars from the register. The person returned 5 minutes later and purchased 70 dollars

in merchandise with the same 100 dollars he stole I gave him 30 dollars change. How much money did the store loose.
Mathematics
1 answer:
Nataliya [291]3 years ago
5 0
Think of it this way. Ignore for now that $100 was stolen.

The purchase of the $70 item for $100 cash with $30 change is a perfectly fair purchase. The store received $100 cash, and the store gave $70 worth of merchandise plus $30 cash.There was no loss to the store there.

The fact that $100 in cash was stolen earlier from cash register means the loss is $100. The legitimate transaction does not affect the loss.

If you have a hard time understanding the loss is $100, then think of it this way.
Reverse the order of the two happenings.

A person walked into a store and bought a $70 item with a $100 bill. He received $30 change. So far, there is no loss to the store. Everything is legit.

That customer later came back to the store and stole $100 from the cash register.

Here we see clearly that the loss is exactly $100. It is simply the $100 stolen from the cash register.
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A company with a fleet of 150 cars found that the emissions systems of only 4 out of the 25 they tested failed to meet pollution
salantis [7]

Answer:

No, there is no strong evidence that the percentage of the fleet out of compliance is different from their initial thought.

Step-by-step explanation:

We are given that a company with a fleet of 150 cars found that the emissions systems of only 4 out of the 25 they tested failed to meet pollution control guidelines.

The company initially believed that 30% of the fleet was out of compliance.

<u><em>Let p = percentage of the fleet that was out of compliance.</em></u>

SO, Null Hypothesis, H_0 : p = 30%   {means that the percentage of the fleet out of compliance is same as their initial thought}

Alternate Hypothesis, H_A : p \neq 30%   {means that the percentage of the fleet out of compliance is different from their initial thought}

The test statistics that will be used here is <u>One-sample z proportion</u> <u>statistics</u>;

                                 T.S.  = \frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }  ~ N(0,1)

where, \hat p = percentage of the fleet out of compliance = \frac{4}{25} = 16%

           n = sample of systems tested = 25

So, <u><em>test statistics</em></u>  =  \frac{0.16-0.30}{{\sqrt{\frac{0.16(1-0.16)}{25} } } } }

                              =  -1.909

The value of the test statistics is -1.909.

<em>Since in the question we are not given with the level of significance at which hypothesis can be tested, so we assume it to be 5%. Now at 5% significance level, </em><u><em>the z table gives critical values between -1.96 and 1.96 for two-tailed test.</em></u><em> </em>

<em>Since our test statistics lies within the range of critical values of z, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.</em>

Therefore, we conclude that the percentage of the fleet out of compliance is same as their initial thought.

3 0
3 years ago
A person places $13000 in an investment account earning an annual rate of 7.4%,
egoroff_w [7]

Answer: r=7.4%=0.074

Move decimal over two places

P=13000

Given as the principal

t=19

Given as the time

V=Pe^{rt}

V=13000e^{0.074( 19)}

Plug in

V=13000e^{1.406}

Multiply

V=53034.856≈53034.86

Use calculator and round to nearest cent

6 0
3 years ago
These are the values in Devante’s data set. (2, 94.5), (3, 89), (4,80), (6, 71), (7, 63) Devante determines the equation of a li
Sedbober [7]
We know that

The residual value is the observed value minus the predicted value.

RESIDUAL VALUE=[OBSERVED VALUE-PREDICTED VALUE]

where

Predicted value.--> the predicted value given the current regression equation

<span>Observed value. --> The observed value for the dependent variable
</span>
find the residuals value

point 1) <span>(2, 94.5)
</span>yˆ=−6x+105.7 

for x=2
Observed value=94.5
Predicted value=-6*2+105.7-----> 93.7
RESIDUAL VALUE=[OBSERVED VALUE-PREDICTED VALUE
so
RESIDUAL VALUE=[94.5-93.7]----> 0.8-----> 1
point (2,1)

point 2) <span>(3, 89)
</span>yˆ=−6x+105.7 

for x=3
Observed value=89
Predicted value=-6*3+105.7-----> 87.7
RESIDUAL VALUE=[OBSERVED VALUE-PREDICTED VALUE
so
RESIDUAL VALUE=[89-87.7]----> 1.3-----> 1
point (3,1)

point 3) <span>(4,80)
</span>yˆ=−6x+105.7 

for x=4
Observed value=80
Predicted value=-6*4+105.7-----> 81.7
RESIDUAL VALUE=[OBSERVED VALUE-PREDICTED VALUE
so
RESIDUAL VALUE=[80-81.7]----> -1.7-----> -2
point (4,-2)

point 4) <span>(6, 71)
</span>yˆ=−6x+105.7 

for x=6
Observed value=71
Predicted value=-6*6+105.7-----> 69.7
RESIDUAL VALUE=[OBSERVED VALUE-PREDICTED VALUE
so
RESIDUAL VALUE=[71-69.7]----> 1.3 -----> 1
point (6,1)

point 5) <span>(7, 63)
</span>yˆ=−6x+105.7 

for x=7
Observed value=63
Predicted value=-6*7+105.7-----> 63.7
RESIDUAL VALUE=[OBSERVED VALUE-PREDICTED VALUE
so
RESIDUAL VALUE=[63-63.7]----> 0.7 -----> 1
point (7,1)

using a graph tool
<span>graph the residual plot for the data set.
the points are
</span>(2,1) (3,1) (4,-2) (6,1) (7,1)

see the attached figure

4 0
4 years ago
Figure 1:
navik [9.2K]

Answer:

The answers are in the picture

Step-by-step explanation:

       

4 0
3 years ago
Please help guys! please please help ​
gtnhenbr [62]
Your image isn’t visible :/
6 0
3 years ago
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