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Dmitriy789 [7]
3 years ago
6

A point P has coordinates (-8, -2). what are its new coordinates after reflection point P across the x -axis

Mathematics
1 answer:
DiKsa [7]3 years ago
3 0

Answer:

y axsis

Step-by-step explanation:

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HELP PLZ! BRAINLIST WILL BE PICKED!
fomenos

Answer:

-0.9

Step-by-step explanation:

hope this helps lovely! lmk if you need an explanation!

3 0
3 years ago
What is the ratio represented by point B?
Komok [63]

6 seconds : 2 meters

which can be reduced to

3 seconds : 1 meter

Answer: 3:1

6 0
3 years ago
Read 2 more answers
Fine the lower and upper quartiles and interquetile range.
Gnom [1K]

Answer:

Lower Quartile = 25.5

Upper Quartile = 61.5

IQR = 36

Step-by-step explanation:

Given data is:

5, 12, 17, 23, 28, 31, 37, 41, 42, 49, 54, 58, 65, 68, 73, 71

The lower quartile is the first quartile and upper quartile is the third quartile.

A median divides the data set in two equal halves.

Lower quartile also known as first quartile is the middle value in the first half.

The first half is:

5, 12, 17, 23, 28, 31, 37, 41

As the number of values is even, the quartile will be the average of two middle values

Q_1 = \frac{23+28}{2} =\frac{51}{2}= 25.5

Upper quartile is the average of middle two values in the second half when the number of values is even.

42, 49, 54, 58, 65, 68, 73, 71

Q_3 = \frac{58+65}{2} = \frac{123}{2} = 61.5

Interquartile range is the difference of third quartile and first quartile

IQR = Q_3 - Q_1 = 61.5-25.5=36

Hence,

Lower Quartile = 25.5

Upper Quartile = 61.5

IQR = 36

7 0
3 years ago
Cos^2x+cos^2(120°+x)+cos^2(120°-x)<br>i need this asap. pls help me​
o-na [289]

Answer:

\frac{3}{2}

Step-by-step explanation:

Using the addition formulae for cosine

cos(x ± y) = cosxcosy ∓ sinxsiny

---------------------------------------------------------------

cos(120 + x) = cos120cosx - sin120sinx

                   = - cos60cosx - sin60sinx

                   = - \frac{1}{2} cosx - \frac{\sqrt{3} }{2} sinx

squaring to obtain cos² (120 + x)

= \frac{1}{4}cos²x + \frac{\sqrt{3} }{2}sinxcosx + \frac{3}{4}sin²x

--------------------------------------------------------------------

cos(120 - x) = cos120cosx + sin120sinx

                   = -cos60cosx + sin60sinx

                   = - \frac{1}{2}cosx + \frac{\sqrt{3} }{2}sinx

squaring to obtain cos²(120 - x)

= \frac{1}{4}cos²x - \frac{\sqrt{3} }{2}sinxcosx + \frac{3}{4}sin²x

--------------------------------------------------------------------------

Putting it all together

cos²x + \frac{1}{4}cos²x + \frac{\sqrt{3} }{2}sinxcosx + \frac{3}{4}sin²x + \frac{1}{4}cos²x - \frac{\sqrt{3} }{2}sinxcosx + \frac{3}{4}sin²x

= cos²x + \frac{1}{2}cos²x + \frac{3}{2}sin²x

= \frac{3}{2}cos²x + \frac{3}{2}sin²x

= \frac{3}{2}(cos²x + sin²x) = \frac{3}{2}

                 

5 0
3 years ago
How many lines of symmetry does the figure have:<br><br> 0<br> 1<br> 2<br> 4
Vlada [557]

Answer:

2

Step-by-step explanation:

i believe this is true

3 0
3 years ago
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