There are 2001 items in that set.
So n(A) = 2001
We can individually count them all out, which is very slow and tedious, or we can use the formula
n-m+1
where,
m = starting value
n = ending value
In this case,
m = 0
n = 2000
So,
n-m+1 = 2000-0+1 = 2001
This formula only works if we increase the number by 1 each time (eg: 6, 7, 8, etc)
Answer:
128
Step-by-step explanation:
First you find the common deoninator.
Step 1: Reduce (simplify) entered fractions to lowest terms, if the case:Fraction: 5 / 6 it's already reduced to lowest terms
Fraction: 11 / 12 it's already reduced to lowest terms
Step 2: Calculate LCM (lowest common multiple) of the reduced fractions' denominators, it will be the common denominator of the compared fractions:Denominator 6, factored = 2 * 3
Denominator 12, factored = 22<span> * 3</span>
LCM (6, 12) = 22<span> * 3 = 12</span>Step 3: Calculate each fraction's expanding number (LCM divided by each fraction's denominator):For fraction: 5 / 6 is 12 : 6 = (22<span> * 3) : 6 = 2</span>
For fraction: 11 / 12 is 12 : 12 = (22<span> * 3) : 12 = 1</span>
Step 4: Expand fractions to bring them to the common denominator (LCM):5 / 6 = (2 * 5) / (2 * 6) = 10 / 12
<span>11 / 12 = (1 * 11) / (1 * 12) = 11 / 12</span>
27 for 3
31 for 4
27 divided by 3 =9
31 divided by 4=7.615
