Answer:
The percentage loss = 10.9375 %
Step-by-step explanation:
Let the cost price = x
Since the marked price is 18.75% above the cost price so the
Marked price = 1.1875 x
When a discount of 25% is allowed on the marked price , the selling price will be Rs. 1425
⇒ Marked price × 0.75 = 1425
⇒ Cost price × ( 1.1875 × 0.75 ) = 1425
⇒ Cost price × ( 0.890625 ) = 1425
⇒ Cost price = 1600
Selling price = 1425
So percentage loss = × 100
% Loss = × 100
% Loss = 10.9375 %
Answer:
The standard deviation reduces when sample size (n) increases
Step-by-step explanation:
From the above information given, we have that mean = 75.5
Standard deviation = 3.5
But Standard deviation = √summation (x-u)/n
This simply implies that when sample (n) is increased there would be a reduction in the standard deviate.
Answer: B
Step-by-step explanation:
I knew I would have 1 foot left so that made sure it wasn’t A then I knew that it the answer had to be in yards so I convert 8 feet into yards which becomes 2.7 so it’s not three which makes I’m not C. So 9 yards minus 2.7 yards would equal the answer B
Answer:
180 miles
Step-by-step explanation:
Step one:
capacity of tank= 18.5gallons
vehicle averages 666 miles per tank.
Hence, the vehicle can travel 666 miles on 18.5 gallons
Required
The distance covered on 5 gallons
Step two:
vehicle can travel 666 miles on 18.5 gallons
the vehicle will go x miles on 5 gallons
cross multiply we have
5*666= 18.5*x
3330=18.5x
divide both sides by 18.5
x= 3330/18.5
x=180 miles
Answer:
Answers may vary but will most likely be close to 2.
Step-by-step explanation
- Given:
first test:38%
second test:76%
SIMULATION FIRST TEST
Randomly select a 2-digit number.
If the digit is between 00 and 35 then you passed the test,else you did not pass the test.
SIMULATION SECOND TEST
Randomly select a 2-digit number.
if the digit is between 00 and 75 then you passed the test,else you did not pass the test.
SIMULATION TRIAL
Perform the simulation of the first test.if you did not pass the first test then perform the simulation of the second test.
Record the number of trials needed to pass the first or second test.
Repeat 20 times and take the average of the 20 recorded number of trials
(what is the sum of recorded values divided by 20).
Note:you will most likely obtain a result of about two trials needed.
