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mart [117]
2 years ago
13

Multiply (x^2+4x+2) (2x^2+3x-4)

Mathematics
2 answers:
algol132 years ago
6 0

Answer:

(x² + 4x + 2)(2x² + 3x - 4) equals 2x⁴ + 11x³ + 12x² - 10x - 8

Step-by-step explanation:

<em>(x² + 4x + 2)(2x² + 3x - 4)</em>

Multiply each term in the first parentheses into the expression in the second parentheses.

<em>2x⁴ + 3x³ - 4x² + 8x³ + 12x² - 16x + 4x² + 6x - 8</em>

Combine like terms.

<em>2x⁴ + 11x³ + 12x² - 10x - 8</em>

So, your answer would be letter choice B.

<em />

umka21 [38]2 years ago
5 0

Answer: B

Step-by-step explanation:

(x^2+4x+2) (2x^2+3x-4)

= x^2 (2x^2+3x-4) + 4x (2x^2+3x-4) +

2 (2x^2+3x-4)

= 2x^4 + 3x3 - 4x^2 + 8x^3 + 12x^2 - 16x + 4x^2 + 6x - 8

= 2x^4 + 11x^3 + 12x^2 - 10x - 8

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Step-by-step explanation:

This is because 20% of 32 is 6.4.

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How do you decompose 1 1/4
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2 years ago
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Whats the absolute value of -8 and 8
Alla [95]

Answer:

16

Step-by-step explanation:

-8--------------------------0---------------------------8

imagine this is a straight line where you can measure the distances.

to get from -8 to 0 we have a distance of 8 units.

so, knowing this, now from 0 to 8 we have another distance of 8 units.

8+8=16

Distance is the absolute value, meaning that it'll always be positive.

4 0
2 years ago
What is the standard form of the equation of the circle x^2 - 4x +y^2 +6y + 4 = 0 ?
dybincka [34]
Answer: (x-2)^2+(y+3)^2 = 9

Side notes
1) This circle has a center of (2,-3)
2) The radius of this circle is 3
3) The graph is shown in the attached image

-------------------------------------------------------------------------------------
-------------------------------------------------------------------------------------

Work Shown:

x^2-4x+y^2+6y+4=0
x^2-4x+y^2+6y+4-4=0-4
x^2-4x+y^2+6y = -4
x^2-4x+4+y^2+6y = -4+4 ... see note 1 below
(x^2-4x+4)+y^2+6y = 0
(x-2)^2+y^2+6y = 0
(x-2)^2+y^2+6y+9 = 0+9 ... see note 2 below
(x-2)^2+(y^2+6y+9) = 9
(x-2)^2+(y+3)^2 = 9

note 1: I'm adding 4 to both sides to complete the square for the x terms. You do this by first taking half of the x (not x^2) coefficient which in this case is -4. So take half of -4 to get -2. Then square this result to get 4

note 2: Like with note 1, I'm completing the square. What's different this time is that this is for the y terms now. The y coefficient is 6. Half of this is 3. Square 3 to get 9. So this is why we add 9 to both sides.

--------------------------------------------------------

So the equation in standard form is (x-2)^2+(y+3)^2 = 9

Note how
(x-2)^2+(y+3)^2 = 9
is equivalent to 
(x-2)^2+(y-(-3))^2 = 3^2

So that second equation listed above is in the form (x-h)^2+(y-k)^2 = r^2
where
h = 2
k = -3
r = 3

making the center to be (h,k) = (2,-3) and the radius to be r = 3

The graph is attached.

5 0
2 years ago
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