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Ivahew [28]
3 years ago
10

Amswer this question

Mathematics
1 answer:
disa [49]3 years ago
7 0

they need to be 8 each sides

well if 4 squares are = to 3 and its a cube then all the sides must be even

so if 3x2=6 and you need the square to have 6 as its sides then you need to get 4x2 which = 8

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Step-by-step explanation:

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Illusion [34]

Answer:

<h2><u>question 1</u></h2>

n^{2} - 20n -96 = 0

use product and sum method

product = -96

sum = -20

numbers needed = ( -24 , 4)

n - 24 = 0

n + 4 = 0

hence <u>n = 24 and n = -4 </u>

<u></u>

<h2><u>Question 2 </u></h2>

<u />x^{2} + 12 x = 48<u />

in the form ax^{2}  +bx +c = 0

= x^{2} +12x - 48

make use of the formula :

\frac{-b+-\sqrt{b^{2} -4ac} }{2a}

replace values to make 2 equations :

1.\frac{-12+\sqrt{12^{2} -4*1*-48} }{2*1} = 3.17

2.\frac{-12-\sqrt{12^{2} -4*1*-48} }{2*1} = -15.2

hence <u>x = 3.17 and x = -15.2</u>

<u />

<h2><u>Question 3 </u></h2>

<u />x^{2} -14x+40=0<u />

use product and sum method

product = 40

sum = -14

numbers needed = (-10 , -4)

x - 10 = 0

x - 4 = 0

hence<u> x = 10 and x = 4</u>

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<h2><u>Question 4 </u></h2>

<u />5b^{2} -20b-18 = 7<u />

in the form ax^{2}  +bx +c = 0

this becomes 5b^{2} -20b-18-7

= 5b^{2} -20b-25

can simplify by 5

= b^{2} -4b-5 =0\\

use product and sum method

product = -5

sum = -4

numbers needed (-5 , 1)

b-5 = 0

b + 1 = 0

hence <u>b = 5 and b = -1</u>

5 0
4 years ago
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Answer:

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2. side side side (SSS)

4. angle angle side (AAS)

Step-by-step explanation:

That was all I could answer. I am not sure about the other 3

5 0
3 years ago
A wise man once said, "500 reduced by 4 times my age is 160." What is his age?
babymother [125]

Answer:

165 years old

Step-by-step explanation:

For now let his age be = x

According to the question,

4x - 500 = 160

4x = 160 + 500

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<u></u>

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<u>Hope it helps!</u>

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<u>Mark it as Brainliest</u>

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3 years ago
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yanalaym [24]

Answer:

It is proved

Step-by-step explanation:

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See attachment for the step by step solution of the given problem.

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