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RideAnS [48]
3 years ago
10

juanita covered the outside of a gift box shaped like a rectangular prism with the paper .The box is 3.2 feet long and 2.1 feet

wide and 2.7 feet high what could be the closest to the total to the surface area
Mathematics
1 answer:
finlep [7]3 years ago
7 0
The approximate answer would be 18.144, but if you round it from the tenths place it would be 18.
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liubo4ka [24]
Mya should put 3/5 in each serving.
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3 years ago
This recipe makes four portions of soup.
Harman [31]

Answer:

you need 1/4 of each listed ingredient

Step-by-step explanation:

divide each measurement by 4

7 0
3 years ago
In a series RL circuit, ET = 120 V, R = 40 Ω, and XL = 30 Ω. What is ER?
Delvig [45]

Answer:

The voltage across resistor is E_{R}=96V

Step-by-step explanation:

We are given with Voltage across terminals of a series RL circuit, E_{T}=120V

And Resistance R=40Ω

And inductor reactance X_{L}=30Ω

Since Resistor and inductor are in series, same current flows through both.

And that current, I = \frac{E_{T}} {Z}

                             =\frac{120}{\sqrt{40^{2}+30^{2}}}= \frac{120}{\sqrt{2500}}

                            = \frac{120}{50}=2.4A

Therefore voltage across resistor, E_{R}=IR=2.4X40=96V

7 0
4 years ago
Please help<br> kkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkk
arlik [135]

Answer:

3,053.6

Step-by-step explanation:

You do need to be more specific, the volume of a sphere is V = 4/3 π r^3, it does not need to be related to a cylinder. So if you know the radius, you can calculate the volume.

Hope this helps!

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5 0
3 years ago
Read 2 more answers
Help again...its for math offering 15 points
Anettt [7]

Answer:

\tan \dfrac{\theta}2 = \dfrac{1}2

Step by step Explanation:

\sin \theta = \dfrac{\text{Perpendicular} }{\text{Hypotenuse}} = \dfrac{12}{15}\\\\\\\cos \theta = \dfrac{\text{Base}}{\text{Hypotenuse}}= \dfrac{9}{15}\\\\\text{Now,}\\\\\tan \dfrac{\theta}2 = \dfrac{\sin \tfrac{\theta}2}{\cos \tfrac{\theta}2}\\\\\\~~~~~~~~=\dfrac{2\cos \tfrac{\theta}2 \sin \tfrac{\theta}2 }{2\cos^2 \tfrac{\theta}2}~~~~~~;\left[\text{Multiply by}~ 2\cos\tfrac{\theta}2 \right]

         =\dfrac{\sin \theta}{1+ \cos \theta}~~~~~~~~~~~~;[2 \sin x \cos x = \sin 2x ~ \text{and}~ 2\cos^2 x =1+\cos 2x]\\\\\\=\dfrac{\tfrac{12}{15}}{1+ \tfrac{9}{15}}\\\\\\=\dfrac{\tfrac{12}{15}}{\tfrac{24}{15}}\\\\\\=\dfrac{12}{15}\times \dfrac{15}{24}\\\\\\=\dfrac{12}{24}\\\\\\=\dfrac{1}2

4 0
2 years ago
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