Question

In a series RL circuit, ET = 120 V, R = 40 Ω, and XL = 30 Ω. What is ER?

Answer 1

Answer:

The voltage across resistor is $E_{R}=96V$

Step-by-step explanation:

We are given with Voltage across terminals of a series RL circuit, $E_{T}=120V$

And Resistance R=40Ω

And inductor reactance $X_{L}=30$Ω

Since Resistor and inductor are in series, same current flows through both.

And that current, I = $\frac{E_{T}} {Z}$

                             $=\frac{120}{\sqrt{40^{2}+30^{2}}}= \frac{120}{\sqrt{2500}}$

                            = $\frac{120}{50}=2.4A$

Therefore voltage across resistor, $E_{R}=IR=2.4X40=96V$