Question

Find the solutions for a triangle with a=16, c=12, b=63, B=63°

Answer 1

Answer:

B. on edg

Step-by-step explanation:

Answer 2

Answer:

The answer is m∠A = 71.6° , m∠C = 45.4° , b = 15.0 ⇒ answer (b)

Step-by-step explanation:

∵ a = 16 , c = 12 , m∠B = 63°

By using cosine rule:

∵ $b=\sqrt{a^{2}+c^{2}-2ac(cosB)}$

∴ $b=\sqrt{16^{2}+12^{2}-2(16)(12)(cos63)}= 15.022$

By using sin rule:

∵ $\frac{16}{sinA}=\frac{15}{sin63}$

∴ $sinA=\frac{16sin63}{15}=0.9504$

∴ m∠A=71.6°

∴ m∠C = 180 - (71.6 + 63) = 45.4°

∴ A = 71.6° , C = 45.4° , b = 15.0