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natima [27]
3 years ago
6

Find the solutions for a triangle with a=16, c=12, b=63, B=63°

Mathematics
2 answers:
Naya [18.7K]3 years ago
7 0

Answer:

B. on edg

Step-by-step explanation:

yKpoI14uk [10]3 years ago
3 0

Answer:

The answer is m∠A = 71.6° , m∠C = 45.4° , b = 15.0 ⇒ answer (b)

Step-by-step explanation:

∵ a = 16 , c = 12 , m∠B = 63°

By using cosine rule:

∵ b=\sqrt{a^{2}+c^{2}-2ac(cosB)}

∴ b=\sqrt{16^{2}+12^{2}-2(16)(12)(cos63)}= 15.022

By using sin rule:

∵ \frac{16}{sinA}=\frac{15}{sin63}

∴ sinA=\frac{16sin63}{15}=0.9504

∴ m∠A=71.6°

∴ m∠C = 180 - (71.6 + 63) = 45.4°

∴ A = 71.6° , C = 45.4° , b = 15.0

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