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Taya2010 [7]
3 years ago
6

PLEASE HELP! 20 POINTS!An equation was created for the line of best fit from the actual enrollment data. It was used to predict

the dance studio enrollment values shown in the
table below:
Month
Enrollment
January February March April May June
Actual 500 400 550 550 750 400
Predicted 410 450 650 650 600 450
Residual 90
-50
-100 -100 150 -50
Analyze the data. Determine whether the equation that produced the predicted values represents a good line of best fit
O No, the equation is not a good fit because the sum of the residuals is a large number
No, the equation is not a good fit because the residuals are all far from zero.
Yes, the equation is a good fit because the residuals are not all far from zero.
Yes, the equation is a good fit because the sum of the residuals is a small number

Mathematics
2 answers:
lakkis [162]3 years ago
3 0

Answer:

B) No, the equation is not a good fit because the residuals are all far from zero.

Step-by-step explanation:

If you add the residuals, you get -60, which is small compared to the scale, but is still far from zero.

MAXImum [283]3 years ago
3 0

Answer:

The answer would be A

Step-by-step explanation:

I took the test :)

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Answer:

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Step-by-step explanation:

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This curve passes through (0,0) point.

Now, the straight line is y = 3x - 6 ....... (2)

Now, solving (1) and (2) we get,

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We will consider y = 3.

Now, y = 3x - 6 has zero at x = 2.

Therefor, the required are = \int\limits^3_0 {(3x)^{\frac{1}{2} } } \, dx - \int\limits^3_2 {(3x - 6)} \, dx

= \sqrt{3} [{\frac{x^{\frac{3}{2} } }{\frac{3}{2} } }]^{3} _{0} - [\frac{3x^{2} }{2} - 6x ]^{3} _{2}

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= 6 - 1.5

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