All categories

2 years ago

Where on a number line is the set of numbers x for which:

Mathematics

1 answer:

sattari [20]2 years ago

3 0

$a)\\|x| < 1\iff x < 1\ \wedge\ x > -1\\\\b)\\|x| < 5\iff x < 5\ \wedge\ x > -5\\\\c)\\|x| > 3\iff x > 3\ \vee\ x < -3$

You might be interested in

HELPPPPPP PLEASEEEEEEEEEE

MA_775_DIABLO [31]

In synthetic division, you start by bringing down the first 1 in the box. Multiply that by the 1 outside the box and get a 1. Put that new 1 under the 2 inside the box and add to get 3. Multiply the outside the box by that 3 to get 3 and put that new 3 under the -3 in the box and add to get 0. Multiply that 0 by the 1 outside the box to get 0. Put that 0 under the 2 and add to get the remainder of 2. Your answer is 2, C.

6 0

3 years ago

A number and +7 is less than or equal to nine

pychu [463]

7 is less than nine

8 0

2 years ago

F(u) = u − 1 u + 1 and g(u) = u + 1 1 − u

Andrew [12]

Answer:

Falso

Step-by-step explanation:

3 0

2 years ago

Which statement correctly describes 2p−5

olga2289 [7]

The coefficient is 2 because it is being multiplied by the p.

5 0

3 years ago

Read 2 more answers

JUST ANSWER PLEASE!!! QUICK

jeka57 [31]

Answer:

Options 1 and 3

Step-by-step explanation:

We should know that, the system of linear equations can be treated as matrices, i.e: we can modify or make any operations provide that we must apply the same operation for all terms of each equation.

Given: the solution for the following system is (2,9)

Px + Qy = R ⇒(1)

Tx + Uy = V ⇒(2)

We will check which system of equation has the same solution.

System A) Px + Qy = R

(P+T)x + (Q+U)y = R+V ⇒(3)

So, By summing (1) and (2) we will get the equation (3)

So, system A has the same solution (2,9)

System B) Px + Qy = R

(P+2T)x + (Q+2U)y = R-2V ⇒(4)

By multiplying equation (2) by 2 and add with equation (1), we will get:

(P+2T)x + (Q+2U)y = R+2V

Which is not the same as equation (4)

So, system B has not the same solution (2,9)

System C) (T-P)x + (U-Q)y = V-R ⇒(5)

Tx + Uy = V

By multiplying equation (1) by -1 and add with equation (2), we will get the equation (5)

So, system C has the same solution of (2,9)

System D) (T-P)x + (Q+U)y = V-R ⇒(6)

Tx + Uy = V

We cannot get equation (6) by the same operation over equation (1)

Note the coefficient of x and y⇒ (T-P) and (Q+U)

They must be (T+P) and (Q+U) OR (T-P) and (Q-U)

So, system D has not the same solution of (2,9)

System E) (5T-P)x + (5U-Q)y = V-5R ⇒ (6)

Tx + Uy = V

By subtract equation (1) from 5 times equation (2), we will get:

(5T-P)x + (5U-Q)y = 5V-R

Which is not the same as equation (6)

So, system E has not the same solution (2,9)

As a conclusion, the systems which have the same solution are:

Options 1 and 3

5 0

2 years ago