A
B or D is your answer
Hope this helps
Step-by-step explanation:
By definition of perimeter, direct observation and Pythagorean theorem, the perimeter of kite OBDE is 38 units. (Correct choice: C)
<h3>How to determine the perimeter of a kite OBDE</h3>
In geometry, the perimeter is the sum of the lengths of the sides of a figure. Herein we must determine the perimeter of a quadrilateral, the kite OBDE, that is, the sum of the lengths of its four sides:, which can be found both by direct observation or by the use of the Pythagorean theorem.
Please notice that the quadrilateral has an axis of symmetry passing through the points O and D, which implies that OB = OE and BD = DE. The length of sides BD and DE is 6 units and the length of the sides OB and DE are:
OB = DE = 0.5 · √(24² + 10²)
OB = DE = 13
Lastly, the perimeter of kite OBDE is p = 2 · 6 + 2 · 13 = 38 units.
To learn more on perimeters: brainly.com/question/6465134
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Answer:
34/40
Step-by-step explanation:
There’s only 6 numbers that are a multiple of 6 within the range 0-40. You subtract 6 from 40 and get. 34
Answer:
m∠2 = 53°
Step-by-step explanation:
We will use two properties of a rhombus to solve this problem.
1). Opposite angles of a rhombus are equal.
2). Diagonals bisect the angles.
Since ∠JFG and ∠JHG are the opposite angles of the rhombus,
m∠JFG = m∠JHG
Since, diagonal FH bisect ∠JHG,
m∠FHJ = m∠GHF = m∠JFH = m∠GFH = 37°
In triangle JFH,
m∠FHJ + m∠JFH + m∠HJF = 180°
37° + 37° + m∠HJF = 180°
m∠HJF = 180 - 74
= 106°
Since, diagonal GJ bisects angle HJF,
m∠FJG = = 53°
Therefore, m∠2 = 53°.