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2 years ago

Help me with this please someone help!!!

Mathematics

2 answers:

Ber [7]2 years ago

4 0

There's a 40% chance that the next cereal box will contain a blue or yellow ring.

Vinvika [58]2 years ago

4 0

40% chance so i'd say about 2/5

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2 1/5 times 3 1/8<br><br> Hhahababahwhvwhwvabwbbwvabahwb

Radda [10]

Answer:

2 1/5 times 3 .18 = 6.875

4 0

3 years ago

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What is the slope? What is the y-intercept? What is the equation of the line (slope intercept form?)

yawa3891 [41]

Answer:

The slope is: m = -²/₅

The y-intercept is: b = -2

The equation of the line: y = -²/₅x - 2

Step-by-step explanation:

The equation of a line in slope intercept form: y = mx + b

The slope: $m=\dfrac{y_2-y_1}{x_2-x_1}$

(-5, 0) ⇒ x₁ = -5, y₁ = 0

(0, -2) ⇒ x₂ = 0, y₂ = -2

So:

$m=\dfrac{-2-0}{0-(-5)}=-\dfrac25$

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2 years ago

At a specific point on a highway, vehicles arrive according to a Poisson process. Vehicles are counted in 12 second intervals, a

morpeh [17]

Answer: a) 4.6798, and b) 19.8%.

Step-by-step explanation:

Since we have given that

P(n) = $\dfrac{15}{120}=0.125$

As we know the poisson process, we get that

$P(n)=\dfrac{(\lambda t)^n\times e^{-\lambda t}}{n!}\\\\P(n=0)=0.125=\dfrac{(\lambda \times 14)^0\times e^{-14\lambda}}{0!}\\\\0.125=e^{-14\lambda}\\\\\ln 0.125=-14\lambda\\\\-2.079=-14\lambda\\\\\lambda=\dfrac{2.079}{14}\\\\0.1485=\lambda$

So, for exactly one car would be

P(n=1) is given by

$=\dfrac{(0.1485\times 14)^1\times e^{-0.1485\times 14}}{1!}\\\\=0.2599$

Hence, our required probability is 0.2599.

a. Approximate the number of these intervals in which exactly one car arrives

Number of these intervals in which exactly one car arrives is given by

$0.2599\times 18=4.6798$

We will find the traffic flow q such that

$P(0)=e^{\frac{-qt}{3600}}\\\\0.125=e^{\frac{-18q}{3600}}\\\\0.125=e^{-0.005q}\\\\\ln 0.125=-0.005q\\\\-2.079=-0.005q\\\\q=\dfrac{-2.079}{-0.005}=415.88\ veh/hr$