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4 years ago

PLZ HELP ME SOLVE THIS! THIS IS MY DOD HE IS HERE FOR SUPPORTING U! PLZ HELP MEH! JUST My 6th grade math

Mathematics

1 answer:

Marat540 [252]4 years ago

3 0

z165 thank me later i guess

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What is 615×351 and how do i do it

netineya [11]

You can use many methods but the way I do it is just multiply it out and you get 215,865

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3 years ago

Daniel buys two apples for every five oranges. If you bought 12 apples, how many oranges dis he buy?

wariber [46]

Answer:

30 oranges

Step-by-step explanation:

2 apples : 5 oranges

12 apples : 30 oranges

because 12 apples is 6 times the original ratio, so we multiply the 5 oranges by 6 too.

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3 years ago

The sum of the interior angles of a 10 sided polygon is how many degress?

11111nata11111 [884]

1,440

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3 years ago

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What is the value of f(x) = 9x when x = -2?

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4 years ago

A survey of 800 women shoppers found that 17% of them shop on impulse. What is the 98% confidence interval for the true proporti

makkiz [27]

Answer:

The 98% confidence interval for the true proportion of women shoppers who shop on impulse is

$0.1391 < p < 0.2009$

Step-by-step explanation:

From the question we are told that

The sample size is n = 800

The sample proportion is $\r p = 0.17$

Given that the confidence level is 98%

The level of significance is evaluated as

$\alpha = 100 -98$

$\alpha = 2$ %

$\alpha = 0.02$

given that this is a two tailed test

$\frac{\alpha }{2} = \frac{0.02}{2} = 0.01$

The critical values obtained from the normal distribution table is

$z_{\frac{\alpha }{2} } = 2.33$

Now the the margin of error is mathematically evaluated as

$MOE = 2.33 * \sqrt{\frac{0.17 (1-0.17)}{800} }$

$MOE = 0.0309$

the 98% confidence interval for the true proportion of women shoppers who shop on impulse is mathematically evaluated as

$0.17 - 0.0309 < p < 0.17 + 0.0309$

$0.1391 < p < 0.2009$

7 0

3 years ago