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Damm [24]
3 years ago
7

What two tissues are found within a vein ?

Biology
1 answer:
katrin [286]3 years ago
5 0
<em>There are two types of vascular tissues witch are Xylem and Phloem</em>.

<em>Xylem is for water transport.</em>

<em>Phloem is for glucose.</em>

<em>Here is an extra just for you! ;)</em>

<em>Parenchyma for lateral transport of both. </em>
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during a natural disaster part of a plnt was damaged if the plant can no longer grow and produce new root cells which of the pla
Usimov [2.4K]

The question is incomplete as it does not have the options which are:

A. Phloem

B. Xylem

C. Apical meristem

D. Root cap

Answer:

The correct answer will be option- Root cap

Explanation:

The plant growth takes place not only above the surface but below the surface also in the roots. Roots continually grow to absorb more water and nutrients to support the growth of the plant.

The roots are protected by a layer of protective cells forming a structure called root cap below the root. The root cap protects the roots, secretes a substance which helps the growth of the root and the sense gravity.

In the given question since the roots are not able to grow therefore the damaged part will be the root cap.

Thus, the root cap is the correct answer.

8 0
3 years ago
Give a example of a mutation that is beneficial and a general explanation of how it is so
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Answer:

Examples of Beneficial Mutation. Mutation, a change in the sequence of genes, is divided into various types such as beneficial, harmful, and neutral, based on their effects. ... Germ-line mutation occurs in the germ cells, and is inherited by the offspring via the reproduction cells.

Explanation:

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3 years ago
Gold has a specific heat of 0.129 J/(g×°C). How many joules of heat energy are required to raise the temperature of 15 grams of
Elodia [21]

Answer:

\boxed {\boxed {\sf 121.905 \ J  }}

Explanation:

We are asked to find the energy given mass, specific heat, and change in temperature. Therefore, we must use this formula;

q= mc \Delta T

The mass is 15 grams and the specific heat is 0.129 J/(g×°C). Let's calculate the change in temperature.

  • ΔT= final temperature - initial temperature
  • ΔT= 85 °C- 22°C = 63°C

Now we know all the values:

m= 15 \ g \ \\c= 0.129 \ J / (g* \textdegree C) \\\Delta T= 63 \ \textdegree C

Substitue the values into the formula.

q= (15 \ g)( 0.129 \ J / (g* \textdegree C)) ( 63 \ \textdegree C)

Multiply the first numbers together. The grams will cancel.

q= (1.935 \ J/ \textdegree C) ( 63 \ \textdegree C)

Multiply again, this time the degrees Celsius cancels.

q= 121.905 \ J

<u>121.905 Joules</u> are required.

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