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Radda [10]
2 years ago
8

Gold has a specific heat of 0.129 J/(g×°C). How many joules of heat energy are required to raise the temperature of 15 grams of

gold from 22 °C to 85 °C?
Biology
2 answers:
Elodia [21]2 years ago
5 0

Answer:

\boxed {\boxed {\sf 121.905 \ J  }}

Explanation:

We are asked to find the energy given mass, specific heat, and change in temperature. Therefore, we must use this formula;

q= mc \Delta T

The mass is 15 grams and the specific heat is 0.129 J/(g×°C). Let's calculate the change in temperature.

  • ΔT= final temperature - initial temperature
  • ΔT= 85 °C- 22°C = 63°C

Now we know all the values:

m= 15 \ g \ \\c= 0.129 \ J / (g* \textdegree C) \\\Delta T= 63 \ \textdegree C

Substitue the values into the formula.

q= (15 \ g)( 0.129 \ J / (g* \textdegree C)) ( 63 \ \textdegree C)

Multiply the first numbers together. The grams will cancel.

q= (1.935 \ J/ \textdegree C) ( 63 \ \textdegree C)

Multiply again, this time the degrees Celsius cancels.

q= 121.905 \ J

<u>121.905 Joules</u> are required.

astraxan [27]2 years ago
5 0

Answer:Approximately

146.54 joules.

Explanation:

The specific heat equation, which states that:

q=mcΔT

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The graph that best shows the general relationship between the temperature of a gas and the speed of the molecules in that gas is B.

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Kinetic energy is the energy that an object or particle has as a result of its motion. When work transferring energy, is done on an object by applying a net force, the object accelerates and goes under kinetic energy.

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hope it helps : )

please mark me brainliest

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