Question

Gold has a specific heat of 0.129 J/(g×°C). How many joules of heat energy are required to raise the temperature of 15 grams of gold from 22 °C to 85 °C?

Answer 1

Answer:

$\boxed {\boxed {\sf 121.905 \ J }}$

Explanation:

We are asked to find the energy given mass, specific heat, and change in temperature. Therefore, we must use this formula;

$q= mc \Delta T$

The mass is 15 grams and the specific heat is 0.129 J/(g×°C). Let's calculate the change in temperature.

• ΔT= final temperature - initial temperature
• ΔT= 85 °C- 22°C = 63°C

Now we know all the values:

$m= 15 \ g \ \\c= 0.129 \ J / (g* \textdegree C) \\\Delta T= 63 \ \textdegree C$

Substitue the values into the formula.

$q= (15 \ g)( 0.129 \ J / (g* \textdegree C)) ( 63 \ \textdegree C)$

Multiply the first numbers together. The grams will cancel.

$q= (1.935 \ J/ \textdegree C) ( 63 \ \textdegree C)$

Multiply again, this time the degrees Celsius cancels.

$q= 121.905 \ J$

121.905 Joules are required.

Answer 2

Answer:Approximately

146.54 joules.

Explanation:

The specific heat equation, which states that:

q=mcΔT