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4 years ago

Geometry math question

Mathematics

2 answers:

Vanyuwa [196]4 years ago

8 0

It's a line q, because it lies on the plane M.

earnstyle [38]4 years ago

6 0

The answer is line q, which is on the plane M, not B.

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PLEASE HELP ASAP!! WILL GIVE BRAINLIEST <br> what is the exact value of tanC

Zielflug [23.3K]

Answer:

tan C = 5/√39

Step-by-step explanation:

tan C = opp/adj

For angle C, the opposite leg is AB, 5.

The adjacent leg is BC, √39.

tan C = 5/√39

6 0

3 years ago

Given: X = r + 2, Y = 2r - 9, and Z = r 2 + 17r + 30. Simplify [X · Y - Z] ÷ X.

musickatia [10]

Answer: r - 24

Step-by-step explanation:

$X=r+2;Y=2r-9;Z=r^2+17x+30$

$\frac{x*y-z}{x}$

$\frac{[(r+2)(2r-9)]-(r^2+17r+30)}{r+2}$

$\frac{(2r^2-9r+4r-18)-(r^2+17r+30)}{r+2}$

$\frac{(2r^2-5r-18)-(r^2+17r+30)}{r+2}$

$\frac{2r^2-5r-18-r^2-17r-30)}{r+2}$

Combine like terms;

$\frac{r^2-22r-48}{r+2}$

Solve the quadratic equation;

$\frac{(r-24)(r+2)}{r+2}$

Simplify;

$r-24$

8 0

4 years ago

Using 4 equal-width intervals, show that the trapezoidal rule is the average of the upper and lower sum estimates for the integr

prisoha [69]

Split up the interval [0, 2] into 4 subintervals, so that

$[0,2]=\left[0,\dfrac12\right]\cup\left[\dfrac12,1\right]\cup\left[1,\dfrac32\right]\cup\left[\dfrac32,2\right]$

Each subinterval has width $\dfrac{2-0}4=\dfrac12$ . The area of the trapezoid constructed on each subinterval is $\dfrac{f(x_i)+f(x_{i+1})}4$ , i.e. the average of the values of $x^2$ at both endpoints of the subinterval times 1/2 over each subinterval $[x_i,x_{i+1}]$ .

So,

$\displaystyle\int_0^2x^2\,\mathrm dx\approx\dfrac{0^2+\left(\frac12\right)^2}4+\dfrac{\left(\frac12\right)^2+1^2}4+\dfrac{1^2+\left(\frac32\right)^2}4+\dfrac{\left(\frac32\right)^2+2^2}4$