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3 years ago

The square of the binomial x-4 has the form x^2-ax+16. What is the value of a?

Mathematics

1 answer:

Serggg [28]3 years ago

8 0

The value of a is 8 because is 2*x*4 so

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Please help<br><br> Boats A, B, C, and D are all the same distance from Boat O.

BlackZzzverrR [31]

Answer:

α = 62°

β = 56°

gamma = 90°

Step-by-step explanation:

ΔAOB is isosceles, so m∠A = m∠ABO = 28

28 + 28 + m∠AOB = 180

m∠AOB = 180 - 28 - 28 = 124

β = 180 - 124 = 56

arcAB = 124

ΔBOC is isosceles. α = m∠BCO = 1/2(arc AB) = 1/2(124) = 62

∠D is inscribed in a semicircle

m∠D = gamma = 90°

7 0

3 years ago

Value of this pronumeral

STatiana [176]

90+80+90+x=360
260+x=360
x=100

4 0

4 years ago

Use the measurements of the scale drawing and original to calculate the scale factor, and then use the scale factor to find the

mina [271]

??????????????????3456

5 0

3 years ago

Read 2 more answers

-3 1/2 - 15/6 helpppppppppp

dezoksy [38]

Answer: will be -6 to that question

4 0

3 years ago

Suppose X, Y, and Z are random variables with the joint density function f(x, y, z) = Ce−(0.5x + 0.2y + 0.1z) if x ≥ 0, y ≥ 0, z

kompoz [17]

$f_{X,Y,Z}(x,y,z)=\begin{cases}Ce^{-(0.5x+0.2y+0.1z)}&\text{for }x\ge0,y\ge0,z\ge0\\0&\text{otherwise}\end{cases}$

is a proper joint density function if, over its support, $f$ is non-negative and the integral of $f$ is 1. The first condition is easily met as long as $C\ge0$ . To meet the second condition, we require

$\displaystyle\int_0^\infty\int_0^\infty\int_0^\infty f_{X,Y,Z}(x,y,z)\,\mathrm dx\,\mathrm dy\,\mathrm dz=100C=1\implies \boxed{C=0.01}$

b. Find the marginal joint density of $X$ and $Y$ by integrating the joint density with respect to $z$ :

$f_{X,Y}(x,y)=\displaystyle\int_0^\infty f_{X,Y,Z}(x,y,z)\,\mathrm dz=0.01e^{-(0.5x+0.2y)}\int_0^\infty e^{-0.1z}\,\mathrm dz$

$\implies f_{X,Y}(x,y)=\begin{cases}0.1e^{-(0.5x+0.2y)}&\text{for }x\ge0,y\ge0\\0&\text{otherwise}\end{cases}$

Then

$\displaystyle P(X\le1.375,Y\le1.5)=\int_0^{1.5}\int_0^{1.375}f_{X,Y}(x,y)\,\mathrm dx\,\mathrm dy$

$\approx\boxed{0.12886}$

c. This probability can be found by simply integrating the joint density:

$\displaystyle P(X\le1.375,Y\le1.5,Z\le1)=\int_0^1\int_0^{1.5}\int_0^{1.375}f_{X,Y,Z}(x,y,z)\,\mathrm dx\,\mathrm dy\,\mathrm dz$

$\approx\boxed{0.012262}$

7 0

3 years ago