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Aneli [31]
3 years ago
8

Divide 28 of soda into two groups so the ratio is 3 to 4​

Mathematics
1 answer:
Musya8 [376]3 years ago
6 0

Answer:Total units would be: 3+4 = 7. value of 1 unit = 28/7 = 4. ratio would be 3(4) & 4(4) = 12 & 16

Step-by-step explanation:

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Find the area of
Vladimir79 [104]

Answer:

18X+6

Step-by-step explanation:

Area of a triangle is half into base into height... forget about other things

5 0
3 years ago
Read 2 more answers
1) x &lt; -14<br> please help i don’t know how to do this
Galina-37 [17]

Answer:  See the diagram below.

This diagram shows a closed filled in circle at -14 on the number line. Also, the shaded region is to the left of the closed circle. This visually represents values that are smaller than -14, or equal to -14.

The filled in circle is used to indicate "include this endpoint". In contrast, an open hole indicates "do not include this endpoint" which is only used if the inequality was x < -14 instead of x \le -14. The "or equal to" portion is why we include the endpoint.

7 0
3 years ago
What is the equation for the hyperbola shown?
amid [387]

Answer:

D. y²/5² - x²/8² = 1

Step-by-step explanation:

A and B are both incorrectly oriented, and D is the only hyperbola that contains the points (0,5) and (0,-5).

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First replace x and y with corresponding x and y values (We will start with x=0 and y=5)

\frac{5^{2}}{5^{2}}-\frac{0^{2}}{8^{2}}=1

Then simplify.

\frac{25}{25}-\frac{0}{16}=1

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1=1

If the result is an equation (where both sides are equal to each other) then the original x and y values inputted are valid. The same is true with x and y inputs x=0 and y=-5, or any other point along   the hyperbola.

6 0
4 years ago
Read 2 more answers
Can someone please help me!!!!!!!!!!!!!!!!!!!!!
N76 [4]

Answer:

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Step-by-step explanation:

5x+7x = 12x

12x - 6 +12 = 180

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5 0
3 years ago
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Dafna1 [17]

Answer:

d. The common ratio is 1.1

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To find it, we divide consecutive terms. For example:

\frac{55}{50} = 1.1

So the correct answer is:

d. The common ratio is 1.1

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3 years ago
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