First, find the z-score:
z = (value - mean) / sdev
= (275 - 280) / 15
= - 0.33
In order to use a standard normal table, we need a positive z-score:
P(z < -0.33) = 1 - P(z < 0.33)
Looking at the table, we find P(z < 0.33) = 0.6293
Therefore:
P(z < -0.33) = 1 - 0.6293 = 0.3707
Hence, you have a probability of about 37% <span>that a randomly selected pregnancy lasts less than 275 days.</span>
1256.64 is the area, because you use this equation- A=πr^2
Answer:
Answer in order, 12,14, (4,3), x2, 4, 12, 3
Step-by-step explanation:
<u><em>PLEASE MARK BRAINLIEST</em></u>
Answer:
730.166666667
Step-by-step explanation:
4,381/6=730.166666667
730.166666667*6=4,381
