Evaluate the expression 3.14(a2 + ab) when a = 4 and b = 3. (Input decimals only, such as 12.71, as the answer.
2 answers:
Answer:
<h2><em>8</em><em>7</em><em>.</em><em>9</em><em>2</em></h2><em>Given,</em>
<em>a</em><em>=</em><em>4</em>
<em>b</em><em>=</em><em>3</em>
<em>Nowz</em>
<em></em>
<em>hope</em><em> </em><em>this</em><em> </em><em>helps</em><em> </em><em>.</em>
<em>Good</em><em> </em><em>luck</em><em> on</em><em> your</em><em> assignment</em><em>.</em><em>.</em><em>.</em>
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Answer:
Option a. $2,040
Step-by-step explanation:
step 1
To find out the amount of the additional passive income last year, subtract the amount earned at her salaried job from Loretta’s income last year
so
step 2
Divide the additional passive income last year by 12 (number of months in a year)
therefore
approximately $2,400 per month
Answer:
The graph of the equation 40.51x+12.45y=666.64 is attached with the answer where the horizontal axis represents the X axis and the vertical axis represents Y axis.
To plot the graph physically just find two points lying on the line. Mark the points on the graph sheet and then join them. This will give you the line represented by the equation.
To find points on the line assume the value of any one variable, substitute it in the equation, then solve the equation to find the value of other variable. For example : assume y = 1; substitute the value of y in the equation;
⇒ 40.51x + 12.45×1 = 666.64
⇒ 40.51x = 666.64 - 12.45
⇒ 40.51x = 654.19
⇒ x =
⇒ x ≈ 16.149
Therefore point ( 16.149 , 1 ) lie on the graph of the equation.
***Only two points are required to plot this graph just because it represents a straight line, that we can conclude just by observing the equation. If in an equation the power of x is 1 or 0 and power of y is 1 or 0 then only it will represent a straight line in 2-D plane.***
Answer:
Probability that the sample mean would be greater than 141.4 millimetres is 0.3594.
Step-by-step explanation:
We are given that Thompson and Thompson is a steel bolts manufacturing company. Their current steel bolts have a mean diameter of 141 millimetres, and a standard deviation of 7.
A random sample of 39 steel bolts is selected.
Let = <u><em>sample mean diameter</em></u>
The z score probability distribution for sample mean is given by;
Z = ~ N(0,1)
where, = population mean diameter = 141 millimetres
= standard deviation = 7 millimetres
n = sample of steel bolts = 39
Now, Percentage the sample mean would be greater than 141.4 millimetres is given by = P( > 141.4 millimetres)
P( > 141.4) = P(
>
) = P(Z > 0.36) = 1 - P(Z
0.36)
= 1 - 0.6406 = <u>0.3594</u>
The above probability is calculated by looking at the value of x = 0.36 in the z table which has an area of 0.6406.