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Svetach [21]
3 years ago
12

Help plz I really don't get it

Mathematics
1 answer:
AURORKA [14]3 years ago
4 0
You answered would be n is greater or equal to 4 but u have to us that symbol
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3y=24 solve by inspection
Ulleksa [173]

Explanation: Division property of equality is dividing both sides of an equation by the same non-zero number does not change the equation.

a÷c=b÷c for c≠0

<u><em>First, you divide by 3 both sides of an equation.</em></u>

<u><em>3y/3=24/3</em></u>

<u><em>Then, simplify.</em></u>

<u><em>24/3=8</em></u>

<u><em>8*3=24</em></u>

<u><em>24/8=3</em></u>

<u><em>y=8 is the final answer.</em></u>

<u><em>Hope this helps!</em></u>

<u><em>Thanks!</em></u>

<u><em>Have a great day!</em></u>

6 0
3 years ago
Read 2 more answers
Robin spent $ 28 at an amusement park For admission and rides. If she paid $6 for admission and rides cost $2 each what is the t
motikmotik

Answer:

11 rides

Step-by-step explanation:

let the total amount be y

and let the number of ride be x

the expression for the situation is y=mx+c

given

total amount=$28

admission fee= $6

cost per ride=$2

we are expected to find x

substitute into the expression we have

28=2x+6

28-6=2x

22=2x

divide boths sides by 2 we have

x=22/2

x=11

the number of rides is 11

4 0
3 years ago
Pablo graphs a system of equations. One equation is quadratic and the other equation is linear. What is the greatest number of p
Nady [450]
For this case we have the following type of equations:
 Quadratic equation:
 y = ax ^ 2 + bx + c&#10;
 Linear equation:
 y = mx + b&#10;
 We observe that when equating the equations we have:
 ax ^ 2 + bx + c = mx + b&#10;
 Rewriting we have:
 ax ^ 2 + (b-m) x + (c-b) = 0&#10;
 We obtain a polynomial of second degree, therefore, the maximum number of solutions that we can obtain is 2.
 Answer:
 The greatest number of possible solutions to this system is:
 c.2
7 0
3 years ago
Read 2 more answers
HELP PLEASE!!! AND NO LINKS THANK YOU.
sveticcg [70]

Answer:

Step-by-step explanation:

Add subtract then divide

5 0
3 years ago
4. Diego is thinking of two positive numbers. He says, "If we triple the first number and
aleksandr82 [10.1K]

Answer:

3<em>x </em>+ 2<em>y</em> = 34. and two possible pairs of positive numbers are  (<em>x</em>, <em>y</em>) = (10, 2) and (<em>x</em>, <em>y</em>) = (4, 11).

Step-by-step explanation:

 Let the First positive number be <em>x</em> and second positive number be <em>y.</em>

Triple of first number = 3<em>x</em>

double of second number = 2<em>y</em>

According to question,

3<em>x </em>+ 2<em>y</em> = 34

Therefore, the equation is 3<em>x </em>+ 2<em>y</em> = 34

So the two possible pair of numbers Diego would be thinking of must satisfy the equation 3<em>x </em>+ 2<em>y</em> = 34

Now,  3<em>x </em>+ 2<em>y</em> = 34

3<em>x </em>= 34 - 2<em>y</em>

Let x = 10 and by substituting its value in above expression,

3 \times 10 = 34 - 2y

30 = 34 - 2y

2y = 34 - 30

2y = 4

y = 2

Therefore first pair (<em>x</em>, <em>y</em>) = (10, 2)

In the same way put x = 4 then,

3<em>x </em>= 34 - 2<em>y</em>

3 \times 4 = 34 - 2y

2y = 34 - 12

2y = 22

y = 11

Therefore first pair (<em>x</em>, <em>y</em>) = (4, 11)

Therefore, (<em>x</em>, <em>y</em>) = (4, 11) and  (<em>x</em>, <em>y</em>) = (10, 2) are the two possible pairs of numbers Diego could be thinking of as these both values satisfy the equation 3<em>x </em>+ 2<em>y</em> = 34.  

8 0
3 years ago
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