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3 years ago

"Through three points there exists one line."

Mathematics

2 answers:

Artemon [7]3 years ago

7 0

Answer:

"Though three points there exists one line."---Incorrect Statement

→"Though two points there exists one line."

This can be explained in the following way.To determine a unique line we need only two points.

→If a line passes through three points, it means these three points are collinear.

AysviL [449]3 years ago

3 0

Answer:

Through any three non collinear points(The points which do not lie on the same line ), there exists exactly one plane.

Step-by-step explanation:

We have given the postulate:

"Through three points there exists one line."

According to the three point postulate:

Through any three non collinear points(The points which do not lie on the same line ), there exists exactly one plane.

Through three non-collinear points X,Y,Z there exists exactly one plane.

The plane XYZ contains atleast three non collinear points...

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HELP! look at image pls

dalvyx [7]

The answers C I’m not sure if I’m too late

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2 years ago

The sum of 6 consecutive integers is 204. what is the fourth number in this sequence?

zloy xaker [14]

Let $x$ by the smallest of the 6 integers. Then

$x+(x+1)+(x+2)+(x+3)+(x+4)+(x+5)=204$

$\implies6x+15=204$

$\implies6x=189$

But 189 is odd, so it cannot be divisible by 6, which means $x$ is not an integer...

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2 years ago

What is the area of the right triangle with sides 10,26 and 24

solniwko [45]

Answer:

Area = 120

Step-by-step explanation:

Area = 1/2 bh

Area = 1/2 (10)(24)

Area = 1/2 (240)

Area = 120

The area of the right triangle is 120

3 0

2 years ago

Read 2 more answers

Points B and B' have symmetry with respect to P. Find the coordinates of P when B is (2, 8) and B' is (2, 2). A. (2, 5) B. (0, 5

Alecsey [184]

Answer:

A. (2, 5)

Step-by-step explanation:

If B and B' have symmetry, then P is a midpoint between those points. We can determinate the location of point P by using the midpoint equation, whose vectorial form is:

$P(x,y) = \frac{1}{2}\cdot B(x,y)+\frac{1}{2}\cdot B'(x,y)$ (Eq. 1)

If we know that $B(x,y) = (2,8)$ and $B'(x,y) = (2,2)$ , then the location of P is:

$P(x,y) = \frac{1}{2}\cdot (2,8)+\frac{1}{2}\cdot (2,2)$

$P(x,y) = (1, 4)+(1,1)$

$P(x,y) = (2, 5)$

Which corresponds to option A.

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3 years ago

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ch4aika [34]

Answer:

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3 years ago