If y = cos(kt), then its first two derivatives are
y' = -k sin(kt)
y'' = -k² cos(kt)
Substituting y and y'' into 49y'' = -16y gives
-49k² cos(kt) = -15 cos(kt)
⇒ 49k² = 15
⇒ k² = 15/49
⇒ k = ±√15/7
Note that both values of k give the same solution y = cos(√15/7 t) since cosine is even.
Answer:
8x+8y
Step-by-step explanation:
red roses = 8 × x = 8x
white roses = 8 × y = 8y
total= 8x+8y
Answer:
Δ JKL ≅ ΔPQR
Step-by-step explanation:
Hopefully this was one of the following statements. You didn't post the statements
Answer:
?
Step-by-step explanation:
Answer:
-1
Step-by-step explanation:
- As you know every number raised to the power of zero is equal to one.
and here we have


