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3 years ago

i When 20 is added to a certain number and the sun is divided by 3, the result is 3 times the number, find the number.

Mathematics

1 answer:

Bingel [31]3 years ago

3 0

Answer:

$let \: the \: number \: be \: x \\ \frac{20 + x}{3} = 3x \\ \frac{3(20 + x)}{3} = (3x)3 \\ 20 + x = 9x \\ 20 = 9x - x \\ 20 = 8x \\ \frac{20}{8} = \frac{8x}{8} \\ x = 2.5$

Step-by-step explanation:

Hope that this is helpful .

Have a great day.

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I am a number greater than $4,000 less than $6,000 by ones digit and 10 digit are the same my 10,000

snow_lady [41]

Answer:

the number is 53611

Step-by-step explanation:

mark me brainliest hope this answer helps

6 0

2 years ago

if the eggs in a basket are removed 2 at a time, 1 egg will remain. if the eggs are removed 3 at a time, 2 eggs will remain. if

Yanka [14]

The least number of eggs that could be in the basket is 119.

Multiple of the number:

The multiple is the numbers you get when you multiply a certain number by an integer.

Given,

If the eggs in a basket are removed 2 at a time, 1 egg will remain.

If the eggs are removed 3 at a time, 2 eggs will remain.

If the eggs are removed 4, 5, or 6 at a time, then 3, 4, and 5 eggs will remain, respectfully.

But if they are taken out 7 at a time, no eggs will be left over.

Here we need to find the least number of eggs in the basket.

Let the number of eggs in the basket be N.

We know that,

if the eggs in a basket are removed 2 at a time, one eggs will remain.

So N is 1 less than a multiple of 2, so

=> N=2A-1

If they are removed 3 at a time, 2 eggs remain.

So N is 2 more, and therefore 1 less than, a multiple of 3, so

=> N=3B-1

If the eggs are removed 4...at a time, then 3...eggs remain,

So N is 3 more, and therefore 1 less than, a multiple of 4, so

=> N=4C-1

Similarly,

For 5,

=> N = 5D - 1

For 6,

=> N = 6E - 1

So, if they are taken out 7 at a time, no eggs will be left over.

So,

N => 7F

Where A,B,C,D,E, and F are any positive integer.

Therefore,

N = 2A-1 = 3B-1 = 4C-1 = 5D-1 = 6E-1 = 7F

Add 1 to all those:

N+1 = 2A = 3B = 4C = 5D = 6E = 7F+1

Through this,

N + 1 = 7F + 1

has to be a common multiple of 2,3,4,5,6.

So, the LCM of 2,3,4,5,6 is 60.

So N+1 is a multiple of 60 which means N is 1 less than a multiple of 60.

So we find the least multiple of 60 that is 1 more than a multiple

of 60.

The multiples are, 60, 59, ....but 59 is not a multiple of 7.

The next multiple of 60 is 120.

1 less than 120 is 119, and sure enough, 119 is a multiple of 7.

So,

=> 119 = 17*7.

Therefore, the least number of eggs that could be in the basket is 119.

To know more about Multiple here

brainly.com/question/5992872

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4 0

2 years ago

What are the coordinates of the intersection of the diagonals of parallelogram LMNO, with vertices L(0,-3), M(-2,1), N(1,5), O(3

ArbitrLikvidat [17]

ANSWER

$\boxed {( \frac{1}{2} , 1)}$

EXPLANATION

The given parallelogram has vertices,

L(0,-3), M(-2,1), N(1,5), O(3,1).

The diagonals of the parallelogram bisect each other.

From the diagram, we can see that, the diagonals have coordinates L(0,-3),N(1,5)

and

M(-2,1),O(3,1).

The midpoint of any of the diagonals will give us the coordinates of intersection of the diagonals.

Recall the midpoint formula,

$(\frac{x_1+x_2}{2}, \frac{y_2+y_1}{2})$

Using L(0,-3),N(1,5) gives,

$(\frac{0+1}{2}, \frac{ - 3+5}{2})$

$(\frac{1}{2}, \frac{ 2}{2})$

$(\frac{1}{2}, 1)$

Or we could have also used,M(-2,1),O(3,1) to get,

$(\frac{-2+3}{2}, \frac{ 1+1}{2})$

$(\frac{ 1}{2}, \frac{ 2}{2})$

$(\frac{ 1}{2}, 1)$

The correct answer is C