Answer:
43.3cm
Step-by-step explanation:
Circumference = PI * diameter.
Circumference = PI * 13.8
Circumference = 43.3cm
Let's solve your equation step-by-step.<span><span><span><span>6n</span>+n</span>+14</span>=0</span>
Step 1: Simplify both sides of the equation.<span><span><span><span>6n</span>+n</span>+14</span>=0</span><span>Simplify: (Show steps)</span><span><span><span>7n</span>+14</span>=0</span>
Step 2: Subtract 14 from both sides.<span><span><span><span>7n</span>+14</span>−14</span>=<span>0−14</span></span><span><span>7n</span>=<span>−14</span></span>
Step 3: Divide both sides by 7.<span><span><span>7n</span>7</span>=<span><span>−14</span>7</span></span><span>n=<span>−2</span></span>
Answer:<span>n=<span>−<span>2</span></span></span>
Answer:
d. - 15
Step-by-step explanation:
The equation for direct variation is
y = kx
We know y =3 when x = -9
3 = k(-9)
Divide by -9
3/-9 = -9k/-9
-1/3 = k
The equation is then
y = -1/3 x
We know y = 5
5 = -1/3 x
Multiply each side by -3
-3*5 = -3*-1/3x
-15 = x
Answer:
black:all
7:23
Step-by-step explanation:
The total number of socks is
8+7+5+3 = 23
ratio of black socks to all socks
black:all
7:23
Answer:
42.5%
Step-by-step explanation:
First we have to complete the table. We know that there are forty part time students so sum(f)=n=40. So, for two courses frequency is 40-11-12=17.
The relative frequency is the proportion of respective frequency and the sum of frequency. So, the missing relative frequency for 1st course is 11/40=0.275.
The missing relative frequency can also be computed as by subtracting given relative frequencies from 1 as sum of relative frequencies is 1. So, 1-0.425-0.3=0.275.
The cumulative frequency of respective class is the sum of frequency of previous classes and frequency of respective class. The missing cumulative frequency is 11+17+12 or 28+12= 40.
So, the complete table is
# of Courses Frequency Relative Frequency Cumulative Frequency
1 11 0.275 11
2 17 0.425 28
3 12 0.3 40
The percent of students takes exactly two courses=0.425*100=42.5%
