The value of the height of the cylinder is 25cm.
According to the statement
we have to find that the height pf the cylinder with the given value of the volume.
So, For this purpose we know that the
The volume of a cylinder is the density of the cylinder which finds that the amount of material it can carry. Cylinder's volume is given by the formula, πr^2h.
From the given information:
The volume of a cylinder is 225π cubic inches, and the radius of the cylinder is 3 inches.
Then
volume = πr^2h
225π = π3^2h
Now, solve it then
225 = 9h
h = 25.
The value becomes 25.
So, The value of the height of the cylinder is 25cm.
Learn more about volume of a cylinder here
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I agree with him that’s the answer
The answer is probably one of the followig:
Natural Number
Whole Number
Integer
Rational
or Real
Answer:
The value of the proposition is FALSE
Step-by-step explanation:
~[(A ⊃ Y) v ~(X ⊃ B)] ⋅ [~(A ≡ ~X) v (B ⊃ X)]
Let's start with the smallest part: ~X. The symbol ~ is negation when X is true with the negation is false and vice-versa. In this case, ~X is true (T)
~[(A ⊃ Y) v ~(X ⊃ B)] ⋅ [~(A ≡ T) v (B ⊃ X)]
Now the parts inside parenthesis: (A ⊃ Y),(X ⊃ B),(A ≡ T) and (B ⊃ X). The symbol ⊃ is the conditional and A ⊃ Y is false when Y is false and A is true, in any other case is true. The symbol ≡ is the biconditional and A ≡ Y is true when both A and Y are true or when both are false.
(A ⊃ Y) is False (F)
(X ⊃ B) is True (T)
(A ≡ T) is True (T)
(B ⊃ X) is False (F)
~[(F) v ~(T)] ⋅ [~(T) v (F)]
The two negations inside the brackets must be taken into account:
~[(F) v F] ⋅ [F v (F)]
The symbol left inside the brackets v is the disjunction, and A v Y is false only with both are false. F v (F) is False.
~[F] ⋅ [F]
Again considerating the negation:
T⋅ [F]
Finally, the symbol ⋅ is the conjunction, and A v Y is true only with both are true.
T⋅ [F] is False.
Explanation:
<u><em>First you subtract by -1 both sides of an equation.</em></u>
<u><em>
</em></u>
<u><em>Then, simplify the number.</em></u>
<u><em>34-1=33</em></u>
<u><em>x>33</em></u>
<u><em>Or interval notation 33,∞ </em></u>
<u><em>Final answer: → x>33 and 33,∞</em></u>
<u><em>Hope this helps!</em></u>
<u><em>Thanks!</em></u>
