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lubasha [3.4K]
2 years ago
8

Evaluate j/4 when j = 12

Mathematics
2 answers:
JulsSmile [24]2 years ago
7 0
Your answer will be 3
Leya [2.2K]2 years ago
7 0

Answer:

3

Step-by-step explanation:

If j=12 then j/4 would be 12/4 which is 3.

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Which two expressions are equivalent?
Elena L [17]

Answer:

C) 4a-2a=a+a

Step-by-step explanation:

4a-2a=2a

2a=a+a

2a=2a

3 0
3 years ago
What is the answer for 30/-31?
mart [117]

Answer:

-0.96774193548

Step-by-step explanation:

kind a mouth full

5 0
2 years ago
A town map has a scale of 2cm:0.5km what is the actual distance for a walk measured at 9cm on the map?
Nastasia [14]

Answer: 2.25 km

Step-by-step explanation:

2 cm = 0.5 km

9 cm = (9 x 0.5)/2

= 2.25 km

4 0
3 years ago
Read 2 more answers
A line is tangent to the circle x^2+y^2=41, at the point (-4,-5)
VashaNatasha [74]
If the equation of the circle is x^2+ y^2 = 41, we must first understand the parts of the equation.
 A general circle's equation is (x-h)^2+(y-k)^2= r^2  
(h.k) is the radius of the circle
r is the radius of the circle
Another useful fact to know is that tangent lines touch the circle at one point (4,5)

Since in our original equation there are no h or k values, we can assume that the center of the circle is (0,0). 

The formula for slope is <u>Y1-Y2</u>
                                   X1-X2
We can break this down with our two points (center and tangent)
  (0,0)    and   (-4,-5)
(X1,Y1) and (X2,Y2)

therefore, we will put the equation as such
<u>0-(-5)= 5</u>  = <em> </em><u><em>5</em></u>
0-(-4)= 4     <em> 4</em>

<em>this is our slope from the center to the point of tangency.</em>

We know that tangent lines are perpendicular to the radius, which we've already found the slope of. Perpendicular lines are opposite reciprocals of the line they are perpendicular to. 

Therefore, we take our slope from center to the tangent, and make it opposite and then take the reciprocal of that slope, which will give us the slope of the tangent line itself. (note: reciprocal means flip the numerator and denominator)
<u>5</u> =  <u>-5</u>  =  <u>-4</u><u>
</u>4     4        5   

Now, we have a point on the line, and the line's slope. We can use slope-intercept equation to find the equation of the line.

Slope-int      y=mx+b
(x,y) is a point,
m is the slope
b is the y intercept  ( the point where x=0, or where its on the y axis)

now we plug things in
(-4,-5) is our point,
<u>-4</u>  is our slope
5

-5=<u>-4</u>(-4)+b       After we plug things in, solve for b
     5

-5= 3.2+b

-1.8= b  or  b=  <u />1 <u>4</u>
                         5

Now we just need to rewrite our equation with all our components.
(-4.-5) = point
<u>-4</u>  = slope<u>
</u>5
1 <u>4</u> = y-intercept<u>
</u>   5

<em>y=</em><u><em>-4</em></u><em> x+ 1 </em><u><em>4</em></u><em>     This is the equation of the tangent line</em><u>
</u><em>    5         5</em>


Hope that helped
7 0
3 years ago
The temperature in degrees Celsius, can be determined using the expression {5}{9}5 9 (F – 32) where F is the temperature in degr
Sergio039 [100]

Answer:

45 degrees Celsius

Step-by-step explanation:

5/9 (113 - 32)

5/9 (81)

45

7 0
2 years ago
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