This is a combination problem. The approach to this is by using the nCr method, where n is the number of total objects and r is the number of success. For example, if you want to get 3 red out of the total 4, then that would be 4C3. That means,
4C3 = 4!/3!(4 - 3)! = 4 ways
If you want to get 2 green out of the total 6, then that would be 6C2. That means,
6C2 = 6!/2!(6-2)! = 15 ways
Therefore, there are a total of 4+15 = <em>19 ways</em>.
Step-by-step explanation:
y= 1
when x=2
here
when x= 3
y=4
The first thing we must do for this case is to find the relationship between the variables.
We have then:
From here, we clear the value of "Y":
On the other hand we have:
From here, we clear the value of "x":
Then, replacing values we have:
On the other hand:
Finally, the perimeter is given by:
Substituting values we have:
Answer:
the perimeter of ABCD is:
44 units
Answer:
The fourth choice
24.2° and 114.2°
Step-by-step explanation:
Complementary angles add up to 90°
Supplementary angles add up to 180°
*a trick to remember this is to know that C is before S in the alphabet, and 90 is before 180, so Complementary is 90 and Supplementary is 180
Step 1: Find the complementary angle
Take 90° and subtract the give angle to find the angle you would need...
90° - 65.8° = 24.2°
Step 1: Find the supplementary angle
Take 180° and subtract the give angle to find the angle you would need...
180° - 65.8° = 114.2°
If the two diagonals are 
and 
, the are of the rhombus is
So, in your case, the area is
The other options are wrong because:
- option A doens't divide by 2, thus getting twice the area of the rhombus
- option B summed the diagonals instead of multiplying them
- option D took the difference of the diagonals.
