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DanielleElmas [232]
3 years ago
5

32.2 - (-15.9) + 10 - 15.9 + 7.8

Mathematics
2 answers:
Delvig [45]3 years ago
8 0
<span>32.2 - (-15.9) + 10 - 15.9 + 7.8= 50

Work

</span>32.2 - (-15.9) = 48.1+10= 58.1
58.1 - 15.9= 42.2
42.2+7.8= 50
ryzh [129]3 years ago
6 0
50.
just use a calculater
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Answer:

VS = 11

Step-by-step explanation:

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3 years ago
Mary is 5 feet tall and Alice is 1.6 meters tall. Who is taller? By how many inches?
8090 [49]

Answer:

Alice

Step-by-step explanation:

5 feet is approximately 1.5 meters so we can say Alice is taller than Mary by 10cm

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3 years ago
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An experiment consists of drawing 1 card from a standard​ 52-card deck. let e be the event that card drawn is a 33. find​ p(e).
Dafna1 [17]

1 out of 52. So 1/52 equals some decimal. Plug in calc.

4 0
3 years ago
Exhibit B: A restaurant has tracked the number of meals served at lunch over the last four weeks. The data shows little in terms
Mekhanik [1.2K]

Answer:

Option E is correct.

The expected number of meals expected to be served on Wednesday in week 5 = 74.2

Step-by-step Explanation:

We will use the data from the four weeks to obtain the fraction of total days that number of meals served at lunch on a Wednesday take and then subsequently check the expected number of meals served at lunch the next Wednesday.

Week

Day 1 2 3 4 | Total

Sunday 40 35 39 43 | 157

Monday 54 55 51 59 | 219

Tuesday 61 60 65 64 | 250

Wednesday 72 77 78 69 | 296

Thursday 89 80 81 79 | 329

Friday 91 90 99 95 | 375

Saturday 80 82 81 83 | 326

Total number of meals served at lunch over the 4 weeks = (157+219+250+296+329+375+326) = 1952

Total number of meals served at lunch on Wednesdays over the 4 weeks = 296

Fraction of total number of meals served at lunch over four weeks that were served on Wednesdays = (296/1952) = 0.1516393443

Total number of meals expected to be served in week 5 = 490

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Checking the options,

74.3 ≈ 74.2

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Hope this Helps!!!

8 0
3 years ago
A geometric sequence is defined by the equation an = (3)3 − n.
Delvig [45]
PART A

The geometric sequence is defined by the equation

a_{n}=3^{3-n}

To find the first three terms, we put n=1,2,3

When n=1,

a_{1}=3^{3-1}

a_{1}=3^{2}

a_{1}=9
When n=2,

a_{2}=3^{3-2}
a_{2}=3^{1}

a_{2}=3

When n=3

a_{3}=3^{3-3}

a_{3}=3^{0}
a_{1}=1
The first three terms are,

9,3,1

PART B

The common ratio can be found using any two consecutive terms.

The common ratio is given by,
r= \frac{a_{2}}{a_{1}}
r = \frac{3}{9}

r = \frac{1}{3}

PART C

To find
a_{11}

We substitute n=11 into the equation of the geometric sequence.

a_{11} = {3}^{3 - 11}

This implies that,

a_{11} = {3}^{ - 8}

a_{11} = \frac{1}{ {3}^{8} }

a_{11}=\frac{1}{6561}
4 0
3 years ago
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