The ratio for this problem is 1:5.
If you are drawing 14 pentagons, you would do 14 x 5.
14 (pentagons) x 5 (line segments) = 70 line segments in total.
The answer is C) 70
Answer:
Step-by-step explanation:
Integrating each term with respect to x, we get:
x^3 x^2
f(x) = 9--------- + 4------- - 4x + C
3 2
We are told that if x = 0, f(x) = -7, and so C must equal - 7.
The solution is
x^3 x^2
f(x) = 9--------- + 4------- - 4x - 7, or f(x) = 3x^3 + 2x^2 - 4x - 7
3 2
There is 1 brother as they would all have the same brother.
Answer:
141.5 in
Step-by-step explanation
AB // CD // EF
12 / 15 = 21 / y (By the property of 3 parallel lines and its transversals)
y = (15*21) / 12 = 26.25
CD // EF // GH
21 / y = x / 10 21 / 26.25 = x / 10
x = (21*10) / 26.25
x = 8
perimeter of ABHG = (y-14) +15 + y + 10 + (5x-3) + x + 21 + 12 = 141.5
This is not going to be a hole number, it's about 4.0666
